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ch4aika [34]
2 years ago
10

Use the prism to answer the question. S in 2 in What is the surface area of the prism? O A 136 in2 B 192 in2 C 240 in2 D272 in2​

Mathematics
2 answers:
Vanyuwa [196]2 years ago
6 0
Is there supposed to be a picture?? I see nothing im sorry. But i can help u cause this is just surface area, quite easy.
I will just give you the formula for surface area of a RECTANGULAR prism:
2 ( width x length + height x length + height x width) or just : 2 (wl + hl + hw)

Have a nice day
Aleks [24]2 years ago
6 0

Answer:

There is no picture

Step-by-step explanation:

please give me brainliest and likes anyway.

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When you multiply the numerator and denominator by the same number, you get an equivilent fraction
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movie tickets cost $9.25 each and a large order of popcorn costs $7.75 what is the total cost of 5 movie tickets and a large ord
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The answer would be 54 dollars
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if one store has 360 items and another store has 100 of the same items, express the ratio of the items
choli [55]
360:100 or 360 to 100
4 0
3 years ago
Expand and simplify bracket please quickly
natulia [17]

Answer:

4y²-1/4 is the required answer

Step-by-step explanation:

(2y -  \frac{1 }{2} )(2y +  \frac{1}{2} ) \\ using \: formula \:  {x}^{2}  - y {}^{2}  = (x - y)(x + y) \\ 4y {}^{2}  -  \frac{1}{4}

4 0
1 year ago
In an arithmetic sequence, a17 = -40 and
Viktor [21]

Answer:

Tn = 2Tn-1 - Tn-2

Step-by-step explanation:

Before we can generate the recursive sequence, we need to find the nth term of the given sequence.

nth term of an AP is given as:

Tn = a+(n-1)d

If a17 = -40

T17 = a+(17-1)d = -40

a+16d = -40 ...(1)

If a28 = -73

T28 = a+(28-1)d = -73

a+27d = -73 ...(2)

Solving both equations simultaneously using elimination method.

Subtracting 1 from 2 we have:

27d - 16d = -73-(-40)

11d = -73+40

11d = -33

d = -3

Substituting d = -3 into 1

a+16(-3) = -40

a - 48 = -40

a = -40+48

a = 8

Given a = 8, d = -3, the nth term of the sequence will be

Tn = 8+(n-1) (-3)

Tn = 8+(-3n+3)

Tn = 8-3n+3

Tn = 11-3n

Given Tn = 11-3n and d = -3

Tn-1 = Tn - d... (3)

Tn-1 = 11-3n +3

Tn-1 = 14-3n

Tn-2 = Tn-2d...(4)

Tn-2 = 11-3n-2(-3)

Tn-2 = 11-3n+6

Tn-2 = 17-3n

From 3, d = Tn - Tn-1

From 4, d = (Tn - Tn-2)/2

Equating both common difference

(Tn - Tn-2)/2 = Tn - Tn-1

Tn - Tn-2 = 2(Tn - Tn-1)

Tn - Tn-2 = 2Tn-2Tn-1

2Tn-Tn = 2Tn-1 - Tn-2

Tn = 2Tn-1 - Tn-2

The recursive formula will be

Tn = 2Tn-1 - Tn-2

5 0
3 years ago
Read 2 more answers
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