The system of equations to determine the number of adult tickets, a, and the number of student tickets, s, the drama club sold is a + s = 1500; 12a + 6s = 16,200. 300 students attended the play.
<h3>Simultaneous equation</h3>
- number of adult tickets = a
- number of student tickets = s
The system of equation:
a + s = 1500
a + s = 150012a + 6s = 16,200
From equation (1)
a = 1500 - s
Substitute into (2)
12a + 6s = 16,200
12(1500 - s) + 6s = 16,200
18,000 - 12s + 6s = 16200
- 12s + 6s = 16200 - 18,000
-6s = -1800
s = -1800 / -6
s = 300
Substitute s = 300 into (1)
a + s = 1500
a + 300 = 1500
a = 1500 - 300
a = 1200
Therefore, there are 300 students and 1200 adults at the play respectively.
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The sum of all the angles in a triangle should always add up to 360° and seeing that this is an isosceles triangle 2 of the angles should be equal.
So there would be 2 30° angles and 360-60=300 so the 3rd angle would be equal to 300° . Hope this helps!
Answer:
13
Step-by-step explanation:
EG=25
EF=12
FG=25-12=13
Okay, well we're gonna find the LCM (least common multiple)
3: 3, 6, 9, 12, 15, 18, 21
7: 7, 14, 21
So...21 days
