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3 years ago

HELP!!! FIRST TO ANSWER GETS BRAINIEST!!!Which of the following equations was used to graph the line shown?

Mathematics

2 answers:

rusak2 [61]3 years ago

8 0

Answer:

Which Equations???

Step-by-step explanation:

Also for coordinates its

( $6,6$ )

And I think I answer is A

Hope this helps.. Have a nice day :)

Lisa [10]3 years ago

7 0

Answer:

y=-x+6

Step-by-step explanation:

A negitive line faces down so this becomes y=-x. so in y=mx+b, b is the point where the line crosses the y axis. So that crosses at 6, so your eqation is y=-x+6

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Plutonium-240 decays according to the function Q(t) = Qoe^-kt

LuckyWell [14K]

Answer:

9990 years

Step-by-step explanation:

The exponential function with given values filled in can be solved for the unknown using logarithms.

Q(t) = 12 = 36e^(-0.00011t)

1/3 = e^(-0.00011t) . . . . . . divide by 36

ln(1/3) = -0.00011t . . . . . . take natural logs

t = ln(1/3)/(-0.00011) . . . . divide by the coefficient of t

t ≈ 9990 . . . years

5 0

2 years ago

What type of probability uses a knowledge of sample spaces as opposed to observations to determine the numerical probability of

Aneli [31]

Answer:

Classical probability

Step-by-step explanation:

Classical property is that type of probability or statistical concept that deals with the measurement of the odds or likelihood of some event.

It is that form of probability that is simplest in approach and includes the equal likelihood of happening or occurrence of an event.

In order to determine the numerical probability of an event, it makes use of the knowledge of sample spaces in contrast with the observations.
It takes a proper note of an event in order to calculate its probability and also it deals with the likelihood of a certain event rather than making observations.

5 0

3 years ago

Read 2 more answers

Which of the following functions are homomorphisms?

Vikentia [17]

Part A:

Given $f:Z \rightarrow Z,$ defined by $f(x)=-x$

$f(x+y)=-(x+y)=-x-y \\ \\ f(x)+f(y)=-x+(-y)=-x-y$

but

$f(xy)=-xy \\ \\ f(x)\cdot f(y)=-x\cdot-y=xy$

Since, f(xy) ≠ f(x)f(y)

Therefore, the function is not a homomorphism.

Part B:

Given $f:Z_2 \rightarrow Z_2,$ defined by $f(x)=-x$

Note that in $Z_2$ , -1 = 1 and f(0) = 0 and f(1) = -1 = 1, so we can also use the formular $f(x)=x$

$f(x+y)=x+y \\ \\ f(x)+f(y)=x+y$

and

$f(xy)=xy \\ \\ f(x)\cdot f(y)=xy$

Therefore, the function is a homomorphism.

Part C:

Given $g:Q\rightarrow Q$ , defined by $g(x)= \frac{1}{x^2+1}$

$g(x+y)= \frac{1}{(x+y)^2+1} = \frac{1}{x^2+2xy+y^2+1} \\ \\ g(x)+g(y)= \frac{1}{x^2+1} + \frac{1}{y^2+1} = \frac{y^2+1+x^2+1}{(x^2+1)(y^2+1)} = \frac{x^2+y^2+2}{x^2y^2+x^2+y^2+1}$

Since, f(x+y) ≠ f(x) + f(y), therefore, the function is not a homomorphism.

Part D:

Given $h:R\rightarrow M(R)$ , defined by $h(a)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)$

$h(a+b)= \left(\begin{array}{cc}-(a+b)&0\\a+b&0\end{array}\right)= \left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right) \\ \\ h(a)+h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)+ \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)=\left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right)$

but

$h(ab)= \left(\begin{array}{cc}-ab&0\\ab&0\end{array}\right) \\ \\ h(a)\cdot h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)\cdot \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)= \left(\begin{array}{cc}ab&0\\-ab&0\end{array}\right)$

Since, h(ab) ≠ h(a)h(b), therefore, the funtion is not a homomorphism.

Part E:

Given $f:Z_{12}\rightarrow Z_4$ , defined by $\left([x_{12}]\right)=[x_4]$ , where $[u_n]$ denotes the lass of the integer $u$ in $Z_n$ .

Then, for any $[a_{12}],[b_{12}]\in Z_{12}$ , we have

$f\left([a_{12}]+[b_{12}]\right)=f\left([a+b]_{12}\right) \\ \\ =[a+b]_4=[a]_4+[b]_4=f\left([a]_{12}\right)+f\left([b]_{12}\right)$

and

$f\left([a_{12}][b_{12}]\right)=f\left([ab]_{12}\right) \\ \\ =[ab]_4=[a]_4[b]_4=f\left([a]_{12}\right)f\left([b]_{12}\right)$

Therefore, the function is a homomorphism.

7 0

3 years ago

Select all expressions that are equivalent to 3x+5+4(x+2)+2<br>pls do not add a link <br>

enot [183]

Answer:

B and D

Step-by-step explanation:

$3x+5+4(x+2)+2 = 7x + 15$

5 0

3 years ago

ANSWER ASAPPP PLSSS. ILL MARK BRAINLIEST TOO

nevsk [136]

Answer:

Step-by-step explanation:

11.04 = 10(1.02)^n

1.104 = 1.02^n

ln 1.104 = ln 1.02^n

ln 1.104 = n ln 1.02

n = ln 1.104/ ln 1.02

n = 4.99630409516

4.99 can be rounded to 5.

So a reasonable domain would be 0 ≤ x < 5

PART B)

f(0) = 10(1.02)^0

f(0) = 10(1)

f(0) = 10

The y-intercept represents the height of the plant when they began the experiment.

f(1) = 10(1.02)^1

f(1) = 10(1.02)

f(1) = 10.2

(1, 10.2)

f(5) = 10(1.02)^5

f(5) = 10(1.1040808)

f(5) = 11.040808

f(1)=10(1.02)^1

f(1)=10.2

Average rate= (fn2-fn1)/(n2-n1)

=11.04-10.2/(5-1)

=0.22

the average rate of change of the function f(n) from n = 1 to n = 5 is 0.22.

3 0

3 years ago

Read 2 more answers