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3 years ago

HELP!!! FIRST TO ANSWER GETS BRAINIEST!!!Which of the following equations was used to graph the line shown?

Mathematics

2 answers:

rusak2 [61]3 years ago

8 0

Answer:

Which Equations???

Step-by-step explanation:

Also for coordinates its

( $6,6$ )

And I think I answer is A

Hope this helps.. Have a nice day :)

Lisa [10]3 years ago

7 0

Answer:

y=-x+6

Step-by-step explanation:

A negitive line faces down so this becomes y=-x. so in y=mx+b, b is the point where the line crosses the y axis. So that crosses at 6, so your eqation is y=-x+6

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3 years ago

|-25.6|+|-11.4| What is the answer to this

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3 years ago

Question is in the picture:)

Bingel [31]

Answer: It would probably be 30

Step-by-step explanation:

The ratio is 10:0 , 20:10 , 30:20 , 40:30 , 50:40, 60:50 , etc…

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3 years ago

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Calculate the total area of the shaded region.

LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

$\stackrel{f(x)}{2x^3-x^2-5x}~~ = ~~\stackrel{g(x)}{-x^2+3x}\implies 2x^3-5x=3x\implies 2x^3-8x=0 \\\\\\ 2x(x^2-4)=0\implies x^2=4\implies x=\pm\sqrt{4}\implies x= \begin{cases} 0\\ \pm 2 \end{cases}$

so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

$\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill$

$\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}$

7 0

2 years ago