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mihalych1998 [28]
4 years ago
10

What is the probability that the roll of a six-sided die will be either even or odd?

Mathematics
2 answers:
Anton [14]4 years ago
3 0

the probability that the roll of a six-sides die will be either even or odd is 1/2 or 50%

MissTica4 years ago
3 0

Answer:

50% -1/2

Step-by-step explanation:

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Can you guys help me out!! Also can y’all show the work!
Lelechka [254]

Answer:

233.3 cubic units

Step-by-step explanation:

Volume of a pyramid

=  \frac{1}{3} × base area × height

The volume of the pyramid

=  \frac{1}{3}  \times (10 \times 10) \times 7

= \frac{1}{3}  \times 100 \times 7

= 233.333...

= 233.3 cubic units (rounded to the nearest tenth)

7 0
3 years ago
Read 2 more answers
Help me please I need to know the answer
Natasha2012 [34]
54 will go in the box that says divisible by 6 and 9.      72 would go under the one that says divisible by 2 and 6.         84 would do under the divisible by 2 and 6.       90 goes under divisible by 5 and 9.       and 96 goes under divisible by 6 and 9.
5 0
4 years ago
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You have 84 stickers to give to your class. There are 14 people in your class. How many stickers will each person get?
Sunny_sXe [5.5K]
6 because 84/16 is 6
4 0
4 years ago
Read 2 more answers
Urgent please help!!!!!!!!!!
zhenek [66]

Answer:

The correct answer is B, the second option

Step-by-step explanation:

(-2, 5/3)

Solve for the first variable in one of the equations, then substitute the result into the other equation.

7 0
2 years ago
2. Margie Spencer wants to have $100,000 in her savings account in 20 years. If her account pays 6.6% annual
WITCHER [35]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill & \$100000\\ P=\textit{original amount deposited}\\ r=rate\to 6.6\%\to \frac{6.6}{100}\dotfill &0.066\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannually, thus two} \end{array}\dotfill &2\\ t=years\dotfill &20 \end{cases}

100000=P\left(1+\frac{0.066}{2}\right)^{2\cdot 20}\implies 100000=P(1.033)^{40} \\\\\\ \cfrac{100000}{1.033^{40}}=P\implies 27288.97\approx P

7 0
2 years ago
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