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weqwewe [10]
3 years ago
14

Solve for x in the function

Mathematics
1 answer:
Zinaida [17]3 years ago
3 0

Answer:

4

Step-by-step explanation:

<h3>2^3= 2x2x2= 8 + 4 =12</h3><h3 /><h3>but it is 16 not 12 so 16 - 12 =4 so that should be ur awnser.</h3><h3 /><h3 /><h3 /><h3>In return can u answer the question that i just asked on my account</h3>
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How do you round the area of a circle with 3.14?
kirill115 [55]

Answer:

(This is a example since you don’t have anything to round to)

Example Answer if the radius is 4 - 50.24

Step-by-step explanation:

Example Radius : 4

Area : 3.14

We have the mulitiply 3.14 times The Example Radius 2 times because The diameter of a circle is 2 times its radius.

( 3.14 x 4 x 4) 50.24

If you know the diameter, it’s a half or 1/2 as large.

Therefore, if the radius was 4, it would be 50.24.

Youre welcome :)

7 0
3 years ago
Help me with these please​
olchik [2.2K]

Step-by-step explanation:

(1) y = x e^(x²)

Take derivative with respect to x:

dy/dx = x (e^(x²) 2x) + e^(x²)

dy/dx = 2x² e^(x²) + e^(x²)

dy/dx = (2x² + 1) e^(x²)

Take derivative with respect to x again:

d²y/dx² = (2x² + 1) (e^(x²) 2x) + (4x) e^(x²)

d²y/dx² = (4x³ + 2x) e^(x²) + 4x e^(x²)

d²y/dx² = (4x³ + 6x) e^(x²)

Substitute:

d²y/dx² − 2x dy/dx − 4y

= (4x³ + 6x) e^(x²) − 2x (2x² + 1) e^(x²) − 4x e^(x²)

= 4x³ + 6x − 2x (2x² + 1) − 4x

= 4x³ + 6x − 4x³ − 2x − 4x

= 0

(2) y = sin⁻¹(√x)

sin y = √x

sin²y = x

Take derivative with respect to x:

2 sin y cos y dy/dx = 1

sin(2y) dy/dx = 1

dy/dx = csc(2y)

Take derivative with respect to x again:

d²y/dx² = -csc(2y) cot(2y) 2 dy/dx

d²y/dx² = -2 csc²(2y) cot(2y)

Substitute:

2x (1 − x) d²y/dx² + (1 − 2x) dy/dx

= 2 sin²y (1 − sin²y) (-2 csc²(2y) cot(2y)) + (1 − 2 sin²y) csc(2y)

Use power reduction formula:

= (1 − cos(2y)) (1 − ½ (1 − cos(2y))) (-2 csc²(2y) cot(2y)) + (1 − (1 − cos(2y))) csc(2y)

= (1 − cos(2y)) (1 − ½ + ½ cos(2y)) (-2 csc²(2y) cot(2y)) + cos(2y) csc(2y)

= (1 − cos(2y)) (½ + ½ cos(2y)) (-2 csc²(2y) cot(2y)) + cot(2y)

= (cos(2y) − 1) (1 + cos(2y)) csc²(2y) cot(2y) + cot(2y)

= (cos²(2y) − 1) csc²(2y) cot(2y) + cot(2y)

= -sin²(2y) csc²(2y) cot(2y) + cot(2y)

= -cot(2y) + cot(2y)

= 0

8 0
3 years ago
What is the result for 0.38 ÷ 19 algorithm
DiKsa [7]
0.02 I think. Have a great day or night
4 0
3 years ago
Solve for x ~<br><br><img src="https://tex.z-dn.net/?f=%5Cbold%5Cpink%7Bx%20%7B%7D%5E%7B2%7D%20%2B%205x%20-%206%20%3D%200%7D" id
Troyanec [42]

\qquad \qquad \rm \large \dag  \: Answer  \: \dag

We have been given a Quadratic equation, where we have to find the real values of x ~

So, let's proceed with middle term splitting method :

\qquad \sf  \dashrightarrow \:  {x}^{2}  + 5x - 6 = 0

\qquad \sf  \dashrightarrow \:  x {}^{2}  + 6x - x - 6 = 0

\qquad \sf  \dashrightarrow \:  {x(}^{} x + 6) - 1(x + 6) = 0

\qquad \sf  \dashrightarrow \: (x + 6)(x - 1) = 0

Now, we have two conditions here~

Either (x + 6) = 0

\qquad \sf  \dashrightarrow \: x =  - 6

or (x - 1) = 0

\qquad \sf  \dashrightarrow \: x = 1

4 0
2 years ago
Use the circle what is the measure of arc ED
polet [3.4K]
Is there supposed to be a graph or a “circle”? you kinda need it to solve the problem lol
4 0
3 years ago
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