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3 years ago

What’s the square root of 8

2 answers:

3 0

It's none of those, but the last is quite close to the exact value. You can find approximate square roots by trial and error: for sqrt(8), 2 is too small and 3 is too big, so try 2.5, 2.6, 2.7, 2.8, and 2.9. You'll find the answer is between 2.8 and 2.9.

Solnce55 [7]3 years ago

3 0

Answer:

the answer is four

Step-by-step explanation:

4x4 = 8

You might be interested in

Instructions:Select the correct answer from each drop-down menu. ∆ABC has vertices at A(11, 6), B(5, 6), and C(5, 17). ∆XYZ has

Akimi4 [234]

to compare the triangles, first we will determine the distances of each side

Distance = ((x2-x1)^2+(y2-y1)^2)^0.5
Solving

∆ABC A(11, 6), B(5, 6), and C(5, 17)

AB = 6 units BC = 11 units AC = 12.53 units
∆XYZ X(-10, 5), Y(-12, -2), and Z(-4, 15)
XY = 7.14 units YZ = 18.79 units XZ = 11.66 units

∆MNO M(-9, -4), N(-3, -4), and O(-3, -15).

MN = 6 units NO = 11 units MO = 12.53 units
∆JKL J(17, -2), K(12, -2), and L(12, 7).
JK = 5 units KL = 9 units JL = 10.30 units
∆PQR P(12, 3), Q(12, -2), and R(3, -2)
PQ = 5 units QR = 9 units PR = 10.30 units
Therefore
we have the ∆ABC and the ∆MNO 
with all three sides equal ---------> are congruent
we have the ∆JKL and the ∆PQR
with all three sides equal ---------> are congruent

let's check

Two plane figures are congruent if and only if one can be obtained from the other by a sequence of rigid motions (that is, by a sequence of reflections, translations, and/or rotations).

1) If ∆MNO ---- by a sequence of reflections and translation --- It can be obtained ------->∆ABC

then ∆MNO ≅ ∆ABC

a) Reflexion (x axis)

The coordinate notation for the Reflexion is (x,y)---- >(x,-y)

∆MNO M(-9, -4), N(-3, -4), and O(-3, -15).

M(-9, -4)-----------------> M1(-9,4)

N(-3, -4)------------------ > N1(-3,4)

O(-3,-15)----------------- > O1(-3,15)

b) Reflexion (y axis)

The coordinate notation for the Reflexion is (x,y)---- >(-x,y)

∆M1N1O1 M1(-9, 4), N1(-3, 4), and O1(-3, 15).

M1(-9, -4)-----------------> M2(9,4)

N1(-3, -4)------------------ > N2(3,4)

O1(-3,-15)----------------- > O2(3,15)

c) Translation

The coordinate notation for the Translation is (x,y)---- >(x+2,y+2)

∆M2N2O2 M2(9,4), N2(3,4), and O2(3, 15).

M2(9, 4)-----------------> M3(11,6)=A

N2(3,4)------------------ > N3(5,6)=B

O2(3,15)----------------- > O3(5,17)=C

∆ABC A(11, 6), B(5, 6), and C(5, 17)

∆MNO reflection------- > ∆M1N1O1 reflection---- > ∆M2N2O2 translation -- --> ∆M3N3O3

The ∆M3N3O3=∆ABC

Therefore ∆MNO ≅ ∆ABC - > check list

2) If ∆JKL -- by a sequence of rotation and translation--- It can be obtained ----->∆PQR

then ∆JKL ≅ ∆PQR

d) Rotation 90 degree anticlockwise

The coordinate notation for the Rotation is (x,y)---- >(-y, x)

∆JKL J(17, -2), K(12, -2), and L(12, 7).

J(17, -2)-----------------> J1(2,17)

K(12, -2)------------------ > K1(2,12)

L(12,7)----------------- > L1(-7,12)

e) translation

The coordinate notation for the translation is (x,y)---- >(x+10,y-14)

∆J1K1L1 J1(2, 17), K1(2, 12), and L1(-7, 12).

J1(2, 17)-----------------> J2(12,3)=P

K1(2, 12)------------------ > K2(12,-2)=Q

L1(-7, 12)----------------- > L2(3,-2)=R

∆PQR P(12, 3), Q(12, -2), and R(3, -2)

∆JKL rotation------- > ∆J1K1L1 translation -- --> ∆J2K2L2=∆PQR

Therefore ∆JKL ≅ ∆PQR - > check list

6 0

3 years ago

Angle XYZ is rotated 270 degrees counterclockwise about the origin to form angle X’Y’Z’. Which statement shows the measure of an

8090 [49]

It is fine that you did not include the measure of angle XYZ in your posting.

This question is testing your knowledge of the four types of transformations.
1) Translations - an item is "slid" to a new location.
2) Reflections - an item is "flipped" (usually over the x-axis or y-axis)
3) Rotations - an item is rotated, usually around the origin (the point (0,0) is the center of most rotations, especially in high school math).
4) Dilations - an item is enlarged or reduced by a certain ratio.

It the first three, the image after the transformation is congruent to the pre-image. It has the same size and shape. It is simply flipped, rotated, slid...

But... in the fourth, dilation, the image now has a different size. It is still, however the same shape.

In geometry terms, after the first three transformations, the image is still "congruent" to the pre-image. After dilation, the image is "similar" but not "congruent."

So... all that to say that when you rotate an angle around the origin, the measure of the angle doesn't change.

So the first choice is correct. The measure of the image of the angle is the same as the measure of the angle.
m∠X’Y’Z’ = m∠XYZ

7 0

3 years ago

Read 2 more answers

Two families went to the event. The first family bought two children's tickets and one adult ticket and paid a total of 8.2 euro

blagie [28]

Answer:

Step-by-step explanation:

step a system of two equations c = child ticket a = adult ticket

eq 1) 2c + 1a = 8.2 multiply by 2

eq 2) 3c + 2a = 14.1

I will multiply eq 1 times TWO and subtract eq 2 from eq 1a)

eq 1a) 4c + 2a = 16.4

eq 2) 3c + 2a = 14.1

subtract (4c - 3c) + (2a -2a) = 16.4 - 14.1

c + 0 = 2.3 euros for one child ticket

Now find the adult ticket price, plug 2.3 for c into eq 1)

eq 1) 2c + 1a = 8.2

eq 1) 2(2.3) + 1a = 8.2 solve for a

4.6 + a = 8.2 substract 4.6 from both sides

a = 8.2 - 4.6

= 3.6 euros for one adult ticket

double check using eq 2) we know c and a values

eq 2) 3c + 2a = 14.1

eq 2) 3(2.3) + 2(3.6) = 14.1

6.9 + 7.2 = 14.1

14.1 = 14.1

5 0

3 years ago

Order 1 1/3 1.34 and 1.3 from least to greatest

qaws [65]

Answer:

1 1/3 as a decimal is 1.333 so i think the answer would be 1.3, 1.34, then 1.333

4 0

3 years ago

It rained 40% of the days during Casey's vacation. What fraction of the days did it rain? Please help me!

Virty [35]

Answer:
40/100=2/5
2/5 is the answer.

6 0

3 years ago