Answer:
The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
Step-by-step explanation:
The area of a sphere is given by the following formula:

In which A is the area, measured in cm², and r is the radius, measured in cm.
Assume that the radius r of a sphere is expanding at a rate of 40 cm/min.
This means that 
Determine the rate of change in surface area when r = 20 cm.
This is
when
. So

Applying implicit differentiation.
We have two variables, A and r, so:



The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
Answer:
Step-by-step explanation:
<u>Solve for y:</u>
Add - 2x to both sides
- 2x + y - 2x = 7 - 2x
- y = 7 - 2x
or
Answer:
-5/2
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-29-(-9))/(15-7)
m=(-29+9)/8
m=-20/8
simplify
m=-5/2
< ABE and < CBD.
Adjacent angles are two angles that have a common vertex and a common side but do not overlap.
17 I think... not sure bout this one not sure about this one not to sure about this one