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Mademuasel [1]
3 years ago
10

Which digit is in the hundreds place in 3,254,107

Mathematics
1 answer:
ozzi3 years ago
5 0
The 1 is in the hundreds place good luck!!!
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Expression in fractured form
pychu [463]

Answer:

Step-by-step explanation:

for the first one it's (x + 5) x (x - 7)

second one it's  (x + 5) x (x + 7)

third one is (x - 5) x ( x + 7)

fourth one is (x -5) x (x - 7)

thats the answer

8 0
3 years ago
How to model 4÷2/3??
stealth61 [152]

Answer:

We have 4 x ( 3 / 2 ) = 12 / 2 = 6;

Step-by-step explanation:

4 0
3 years ago
Hi what is the answer for this?
saw5 [17]
This is a common factor problem.

Pencils come in a pack of 12
Erasers come in a pack of 10

First, break the number into their prime factors(the idea is that we will break the number down into its smallest multiples, which are prime numbers):
10 = 2 * 5
12 = 2 * 2 *3

So now we take the unique multiples of each number, and when we multiply them together, we will get the smallest number that both 10 and 12 can be divided into(this is what the problem is asking for)
We have (2*2*3) that comes from 12, and the only unique number that comes from the 10 is (5)
So now, we multiply:
2*2*3*5=60
However, this isn't exactly out answer. Now we have to divide our answer by the number of each this in the pack to know how many packs to buy.
60/12=5 packs of pencils
60/10= 6 packs of erasers

I hope this helps. Let me know if you have any questions!!
5 0
3 years ago
Read 2 more answers
The function h(t)=16t^2+144 represents the height , h(t) , in feet , of an object from the ground at t seconds after it is dropp
mafiozo [28]
0≤h(t)≤144, which means that the height of the object can be between 0 and 144 feet, including those limits.
4 0
3 years ago
Which of the following is a solution to the following system of inequalities?
iren2701 [21]

Option D: (0,3) is the solution to the inequalities.

Explanation:

From the given graph, we can see that the equation of the inequalities are

$y>-x+1$ and $y\leq 2 x+3$

To determine the coordinate that satisfies the inequality, let us substitute the coordinates in both of the inequalities $y>-x+1$ and $y

Thus, we have,

Option A: (1,-1)

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$, we get,

y>-x+1\implies-1>0 is not true.

$y\leq 2 x+3 \implies -1\leq 5 is true.

Since, only one equation satisfies the condition, the coordinate (1,-1) is not a solution.

Hence, Option A is not the correct answer.

Option B: (-4,0)

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$, we get,

y>-x+1\implies0>5 is not true.

$y\leq 2 x+3 \implies 0\leq -5 is not true.

Since, both the equations does not satisfy the condition, the coordinate (-4,0) is not a solution.

Hence, Option B is not the correct answer.

Option C: (3,-2)

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$, we get,

y>-x+1\implies-2>-2 is not true.

$y\leq 2 x+3 \implies -2\leq 9 is true.

Since, only one equation satisfies the condition, the coordinate (3,-2) is not a solution.

Hence, Option C is not the correct answer.

Option D: (0,3)

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$, we get,

y>-x+1\implies3>1 is true.

$y\leq 2 x+3 \implies 3\leq 3 is true.

Since, both equation satisfies the condition, the coordinate (0,3) is a solution.

Hence, Option D is the correct answer.

4 0
3 years ago
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