All categories

3 years ago

75/100 in its simplest form

Mathematics

2 answers:

Oxana [17]3 years ago

6 0

3/4 is the answer for your question

____ [38]3 years ago

3 0

The greatest common factor of both numbers is 25:
 $\frac{75}{100} / 25 \\ \frac{75/25}{100/25} \\ \frac{3}{4}$
75/100, in its simplest form, is 3/4.
Hope this helps!

You might be interested in

Hannah’s favorite toy character is sold wearing one of many outfits. An outfit consists of one shirt, one pair of pants, and one

Serggg [28]

There is a 1/6 probability

8 0

3 years ago

Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 StartFraction negative 5 minus StartRoot 13 EndRoot Over 2

boyakko [2]

Given:

The quadratic equation is $x^{2}=-5 x-3$

We need to determine the solutions of the quadratic equation.

Solution:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

$x^{2}+5 x+3=0$

The solution of the equation can be determined using quadratic formula.

Thus, we get;

$x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 1 \cdot 3}}{2 \cdot 1}$

$x=\frac{-5 \pm \sqrt{25-12}}{2 }$

$x=\frac{-5 \pm \sqrt{13}}{2 }$

Thus, the two roots of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

Hence, the solutions of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

6 0

3 years ago

Read 2 more answers

A group of 25 employees want to go out for a group dinner. 18 employees want to go to Restaurant A. 7 employees want to go to Re

Pie

Answer:

28 percent

Step-by-step explanation:

i dont know the rest

8 0

2 years ago

There are 15 students in the 8th grade. The students are randomly placed into three different algebra classes of 5 students each

xeze [42]

Answer:

The probability is $\frac{6}{91}$ ≅ $0.0659$

Step-by-step explanation:

Let's analyze the question.

There are 15 students in the 8th grade.

The students are randomly placed into three different algebra classes of 5 students each.

We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.

One possible way to solve this question is to think about the product probability rule.

We can use it because we are in an equiprobable space. (And also the events are independent).

Let's set for example a class for Evan.

The probability that Evan will be in a class is $1$

Then for Terry there are $4$ places out of $14$ that puts Terry in the Evan's class.

We write $1.\frac{4}{14}$

Finally for Trevor there are $3$ places out of the remaining $13$ that puts Trevor in the same class with Evan and Terry.

Using the product rule we write :

$1.\frac{4}{14}.\frac{3}{13}=\frac{6}{91}$

The probability of the event is $\frac{6}{91}$ ≅ $0.0659$

5 0

3 years ago

Write the algebraic expression described.

Aleksandr [31]

Answer:-

90°-f measure

Step-by-step explanation:

If f is one angle it's complementary is 90°-f

Prove:- 90°-f+f°= 90°

Hope this helps you.

5 0

3 years ago