Answer:no, (5,1) is not a solution for the equation. (1/7,1) will be a solution for the equation.
Step-by-step explanation:
one way to do it is to plug 1 as the y-value into the first equation which does work but when you plug 5 as the x-value and 1 as the y-value in the second equation, it will get you to 41 which does not match so it will not be an equation. the other way to check is to solve by substitution which for the first equation, you divide both side by -5 and get y=1 then substitute y with 1 in the second equation and subtract both side by 6 and get 7x=1 and divide both side by 7 to get 1/7. the y-value match but the x-value don't so (5,1) is not a solution.
In a circle, the arc is two times the length of the angle.
EFG = 98°
98 x 2 = 196
Minor arc EG = 196°
Hopefully this helps :)
Answer:
see explanation
Step-by-step explanation:
(a)
= 1 ( any value divided by itself = 1 )
(b)
= a ( any value divide by 1 is the value itself )
(c)
×
= 
The product of 2 fractions is the product of the numerators divided by the product of the denominators
(d)
÷
= 
To divide 2 fractions, leave the first fraction, change division to multiplication and turn the second fraction upside down, that is
÷
=
×
= 
(e)
+
= 
Since the fractions have a like denominator, add the numerators leaving the denominator. This applies to subtraction also
(f)
-
= 
See explanation for part (e)