Question

How could I solve y= 2x^2 + 16x - 66 By using quadratic formula?

Answer 1

Answer: the solutions are

x = 3 or x = - 11

Step-by-step explanation:

The given quadratic equation is expressed as

y = 2x² + 16x - 66 = 0

The equation is already in the standard form of ax² + bx + c

The general formula for solving quadratic equations is expressed as

x = [- b ± √(b² - 4ac)]/2a

From the equation given,

a = 2

b = 16

c = - 66

Therefore,

x = [- 16 ± √(16² - 4 × 2 × - 66)]/2 × 2

x = [- 16 ± √(256 + 528)]/4

x = [- 16 ± √784]/4

x = (- 16 + 28)/4 or x = (- 16 - 28)/4

x = 12/4 or x = - 44/4

x = 3 or x = - 11

Answer 2

Answer:

The answer to your question is x₁ = 3  x₂ = -11

Step-by-step explanation:

Data

                    y = 2x² + 16x - 66

In the quadratic formula, we use the coefficients

a = 2

b= 16

c = -66

Formula

$x = \frac{-b +- \sqrt{b^{2}- 4ac } }{2a}$

Substitution

x =  $\frac{- 16 +-\sqrt{16^{2} - 4(2)(-66)}}{2(2)}$

Simplification

$x = \frac{-16 +- \sqrt{256 + 528}}{4}$

$x = \frac{-16 +- \sqrt{784}}{4}$

$x = \frac{-16 +- 28}{4}$

$x_{1} = \frac{-16 + 28}{4}$

$x_{1} = \frac{12}{4}$

$x_{1} = 3$

$x_{2} = \frac{-16 - 28}{4}$

$x_{2} = \frac{-44}{4}$

$x_{2} = -11$