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yulyashka [42]
2 years ago
12

Use the discriminant to find the number of real solutions of the equation 3x^2 – 5x + 4 = 0

Mathematics
2 answers:
kykrilka [37]2 years ago
8 0
To use the discriminant, first identify a, b, and c. In your equation a= 3 b = -5 and c = 4. Now plug into the discriminant b^2 - 4ac. Substituting yields (-5)^2 - 4(3)(4). Simplifying, 25 - 48 = -23. Since the discriminant has a negative value, there is no real solution to this equation.
Virty [35]2 years ago
4 0
To use the discriminant, first identify a, b, and c. In your equation a= 3 b = -5 and c = 4. Now plug into the discriminant b^2 - 4ac. Substituting yields (-5)^2 - 4(3)(4). Simplifying, 25 - 48 = -23. Since the discriminant has a negative value, there is no real solution to this equation.
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The number w and 0.8 are additive inverses.
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Since, the number w and 0.8 are additive inverses.

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Since, 'w' and '0.8' are additive inverses of each other such that w + 0.8 = 0

Therefore, the value of 'w' should be '-0.8' so that -0.8 + 0.8 = 0.

So, the value of 'w' is =0.8

Now, Refer to the attached image which represents the position of 0.8 , w ( that is -0.8) and the sum of 0.8 and w.

Sum of 0.8 and w = 0.8 + w

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3 0
3 years ago
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Expand the function f(x)=(x+5)^3
Fudgin [204]

Answer:

(x-5)^3

Step-by-step explanation:

(x-5)^3. (x−5)3 ( x - 5 ) 3

5 0
2 years ago
Easy Multiple Choice Questions about expressions and linear equations / ASAP / Will mark brainliest / 25 Points
nata0808 [166]

Answer:

1.C

2.A

3.D

4.C

5.B

6.A

7.B

8.C

9.A

10. D

Step-by-step explanation:

For Problem 1, the work is as follows:

2(3x-1)+x\\Distribute\\6x-2+x\\7x-2

For Problem 2, the work is as follows:

(3x^{2} +6x+4) - (-x^{2} +2x-1)\\Distribute -\\(3x^{2} +6x+4) + (x^{2} -2x+1)\\Combine\\4x^{2} +4x+5

For Problem 3, the work is as follows:

5b-(a+c)^{2} \\5(3) - (-1+-4)^{2} \\15 - (-5)^{2} \\15-25\\-10

For Problem 4, the work is as follows:

4x-8 = -12\\+8\\4x = -4\\-4/4 = -1\\x = -1

For Problem 5, the work is as follows:

\frac{1}{2} (12x-6) = 2x-15\\Distribute\\\\6x - 3 = 2x -15\\+3\\6x = 2x -12\\-2x\\4x = -12\\-12/4\\x = -3

For Problem 6, the work is as follows:

17 *0.06 = 1.02\\17+1.02 = 18.02

For Problem 7, the work is as follows:

x = (2,0)\\y = (0,-1)\\\frac{rise}{run} \\y = \frac{1}{2} x-1

For Problem 8, the work is as follows:

y_{2} -y_{1} \\x_{2} -x_{1} \\-1-1 = -2\\0-(-2) = 2\\Slope = -1

For Problem 9, the work is as follows:

3y - 2x +6 = 0\\-3y\\(-3y - -2x+6)/-3\\y = \frac{2}{3} x -2

For Problem 10, the work is as follows:

(y-3) = -2(x-1)\\Distribute\\(y-3) = -2x+2\\+3\\y = -2x +5

Hope this Helps!

4 0
2 years ago
SOLUTION: y = 5x + 7 what is the value of y
Nat2105 [25]
There are an infinite number of solutions given the information you provided. For every real value of x there will be a corresponding real value of y.

y=5x+7  Has not restriction upon the domain or range...

What is the value of y?  5x+7 
8 0
3 years ago
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