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andreev551 [17]
3 years ago
5

What's the solution of this equation?

Mathematics
1 answer:
Aneli [31]3 years ago
6 0
X = 5x + 6

Bring the x terms to the same side
x - x = 5x + 6 - x

0 = 4x + 6

Move the 6 to the opposite side
0 -6 = 4x + 6 - 6
-6 = 4x

Divide by 4
x = - 3/2

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dedylja [7]

Answer:

i think the answer is either E. or B. i'm not sure if i'm right but if someone can correct me if i'm wrong .

Step-by-step explanation:

6 0
3 years ago
Suppose that an airline quotes a flight time of 128 minutes between two cities. Furthermore, suppose that historical flight reco
ANTONII [103]

Answer:

(a) The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{b-a};\ a

(b) The value of P (129 ≤ X ≤ 146) is 0.3462.

(c) The probability that a randomly selected flight between the two cities will be at least 3 minutes late is 0.4327.

Step-by-step explanation:

The random variable <em>X</em> is defined as the flight time between the two cities.

Since the random variable <em>X</em> denotes time interval, the random variable <em>X</em> is continuous.

(a)

The random variable <em>X</em> is Uniformly distributed with parameters <em>a</em> = 10 minutes and <em>b</em> = 154 minutes.

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{b-a};\ a

(b)

Compute the value of P (129 ≤ X ≤ 146) as follows:

Apply continuity correction:

P (129 ≤ X ≤ 146) = P (129 - 0.50 < X < 146 + 0.50)

                           = P (128.50 < X < 146.50)

                           =\int\limits^{146.50}_{128.50} {\frac{1}{154-102}} \, dx

                           =\frac{1}{52}\times \int\limits^{146.50}_{128.50} {1} \, dx

                           =\frac{1}{52}\times (146.50-128.50)

                           =0.3462

Thus, the value of P (129 ≤ X ≤ 146) is 0.3462.

(c)

It is provided that a randomly selected flight between the two cities will be at least 3 minutes late, i.e. <em>X</em> ≥ 128 + 3 = 131.

Compute the value of P (X ≥ 131) as follows:

Apply continuity correction:

P (X ≥ 131) = P (X > 131 + 0.50)

                 = P (X > 131.50)

                 =\int\limits^{154}_{131.50} {\frac{1}{154-102}} \, dx

                 =\frac{1}{52}\times \int\limits^{154}_{131.50} {1} \, dx

                 =\frac{1}{52}\times (154-131.50)

                 =0.4327

Thus, the probability that a randomly selected flight between the two cities will be at least 3 minutes late is 0.4327.

6 0
3 years ago
6(w – 2) + 2 = 2(3w - 5)
galben [10]

Answer:

Infinite Solutions

Step-by-step explanation:

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At top speed, a coyote can run at a speed of 44 miles per hour. if a coyote could maintain its top speed, how far could it run i
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The anwser would be B -11 miles you just have to divide by 4
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It snowed 72 cm in 24 hours
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Answer:

Step-by-step explanation:

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