All categories

3 years ago

If 3m+2n=16 and m−2n=0, then what is the value of m?

Mathematics

1 answer:

umka21 [38]3 years ago

7 0

Answer:

m= 4

Step-by-step explanation:

3m +2n= 16 -----(1)

m -2n= 0 -----(2)

From (2):

m= 2n -----(3) (+2n on both sides)

subst. (3) into (1):

3(2n) +2n= 16

6n +2n= 16

8n= 16 (simplify)

n= 16 ÷8

n= 2

subst. n=2 into (3):

m= 2(2)

m= 4

You might be interested in

What is 0.6 of 120 really hard and i need an answer for today

ddd [48]

$0.6\ of\ 120\ is\\\\0.6\cdot120=6\cdot12=72\leftarrow Answer$

5 0

3 years ago

Use substitution to solve the system. X= ? Y= ? 5x+4y = -10 x = 3y+17

nikklg [1K]

Answer:

x=3.4

y=-6.75

Step-by-step explanation:

5x+4y=-10 (equation 1 )

-5x+3y=-17 (equation 2)

7y=-27

y=-6.75

substitution (equation 1 ) y=-6.75

5x-27=-10

5x=17

x=3.4

4 0

3 years ago

Hello can you help me with this problem ?

Lelechka [254]

Step-by-step explanation:

please mark me as brainlist please

3 0

2 years ago

The region bounded by y=(3x)^(1/2), y=3x-6, y=0

Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is $y = (3x)^{\frac{1}{2} }$

⇒ $y^{2} = 3x$ ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

$y^{2} - y - 6 = 0$

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = $\int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx$

= $\sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}$

= $[\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} } }{3}] - [13.5 - 18 - 6 + 12]$

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0

2 years ago

How many pennies are in 1 months lion dollars?

My name is Ann [436]

Ten thousand pennies

5 0

2 years ago

Read 2 more answers