Answer: 3(three)
Explanation:
In the biosynthesis of phosphatidylethanolamine from ethanolamine and triglyceride, 3 high energy molecules are used in the first and second step.
The first steps occur in the cytosol, where ethanolamine is phosphorlated with ATP to give phosphoethanolamine and ADP by the enzyme ethanolamine kinases, and in the next reaction which is the rate-limiting step, phosphoethanolamine react with cytidine triphosphate (CTP) to form cytidine diphosphoethanolamine. In this reaction two molecules of phosphate group is given off.
The third step occurs in the endoplasmic reticulum CDP-ethanolamine react with diacylglycerol to form phosphatidylethanolamine.
The answer is Three high energy molecules. One molecule of ATP to form phosphorylethanolamine and two molecules of ATP to regenerate CTP from CMP.
you increase the chances of the existing bacteria mutating and becoming resistant, therefore making it harder to treat the next time around.
Cerebellum is part that helps us keep from falling.
In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of allele a is 0.2. The frequency of individuals that are heterozygous for this allele is 0.32.
<h3>Hardy Weinberg Equilibrium Principle </h3>
- A stable, idealized population's constant frequency of alleles and genotypes is described by the Hardy-Weinberg equilibrium principle.
- In a sizable population, random mating, or spontaneous mutations are necessary for Hardy-Weinberg equilibrium.
The Hardy-Weinberg equation dictates that the sum of the allele frequencies for each allele at the locus must equal 1, therefore p + q = 1. The Hardy-Weinberg equation is also written as p2 + 2pq + q2 = 1, where p is the population's frequency of the "A" allele and q is that of the "a" allele.
The homozygous genotype AA frequency is represented by p2, the homozygous genotype aa frequency by q2, and the heterozygous genotype aa frequency by 2pq in the equation.
Here, q = 0.2. Because of this, p = '1- q = 1 - 0.2 = 0.8.
The population of individuals who are heterozygous will now be 2pq, or 2 * 0.8 * 0.2 = 0.32.
Hence, This indicates that the population is heterozygous with a frequency of 0.32.
To learn more about Hardy Weinberg Principle refer to:
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