Answer:
23.54 m
Step-by-step explanation:
Applying
cos∅ = adjacent(A)/hypotenuse(H)
cos∅ = A/H................ Equation 1
make H the subject of the equation
H = A/cos∅............ Equation 2
Given: A = 15 m, ∅ = 25°
Substitute into equation 2
H = 15/cos25
H = 16.55 m
Also,
tan∅ = opposite(O)/Adjacent(A)
tan∅ = O/A............Equation 3
Make O the subject of the equation
O = Atan∅.......... Equation 4
Substituting into equation 4
O = 15(tan25°)
O = 6.99 m.
From the diagram,
The height of the goal post before snap = H+O
The height of the goal post before snap = 16.55+6.99
The height of the goal post before snap = 23.54 m
First. y=2x
second d is correct
third is a
Answer:
total surface area = 76 sq.cm
Step-by-step explanation:
total surface area of cuboid = 2 ( lb + lh + bh )
( where l is length , b is width and h is height )
so, surface area :
= 2[ (5×4) + (5×2) + (2×4) ]
= 2 [ 20 + 10 + 8 ]
= 2 × 38
= 76 sq.cm
Answer:
3x
Step-by-step explanation:
