Come on now, check your book on the "product to sum" identities
![\bf cos({{ \alpha}})sin({{ \beta}})=\cfrac{1}{2}[sin({{ \alpha}}+{{ \beta}})\quad -\quad sin({{ \alpha}}-{{ \beta}})]](https://tex.z-dn.net/?f=%5Cbf%20cos%28%7B%7B%20%5Calpha%7D%7D%29sin%28%7B%7B%20%5Cbeta%7D%7D%29%3D%5Ccfrac%7B1%7D%7B2%7D%5Bsin%28%7B%7B%20%5Calpha%7D%7D%2B%7B%7B%20%5Cbeta%7D%7D%29%5Cquad%20-%5Cquad%20sin%28%7B%7B%20%5Calpha%7D%7D-%7B%7B%20%5Cbeta%7D%7D%29%5D)
Answer:
<u>k = 3</u>
Step-by-step explanation:
one zero of p(x) = kx²– 14 x + 8 is 6 times the other.
let the zeros are ⇒ a and 6a
the equation kx²– 14 x + 8
can be written as k ( x²/k– 14/k x + 8/k)
So, a * 6a = 8/k ⇒ (1)
And a + 6a = 14/k ⇒ (2)
from (2) k = 14/(a + 6a) = 14/(7a) = 2/a
∴ a = 2/k
Substitute at (1)
a * 6a = 8/k
2/k * 12/k = 8/k
solve for k
24/k = 8
k = 24/8 = 3
<u>the value of k = 3</u>
And the zeros will be 2/3 and 4
Answer:
5.42$
Step-by-step explanation:
Please mark brainliest?
2b + 32 = 8
1. Subtract 32 from 8 which is -24
2b = -24
2. Divide both sides by 2, to make b by itself
b = -12
Answer: 8
Step-by-step explanation:
For this problem, we would have to subtract the larger number of dogs by the smaller number of dogs. Zaierr has 10 dogs, and Lamarr has 2 dogs. We would have to subtract the number 10 by the number 2 to get our answer.
10 subtracted by 2 is equal to the number 8.
The answer to our question is 8.
