I want points!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Hello :
<span>the parabola's equation is : f(x) = a(x+3)²-1
</span><span>the coefficient of the squared expression in the parabola's equation is : a
but ; f(4) = 0
0 = a(4+3)²-1
49a-1=0.....a=1/49
f(x) = 1/49(x-3)²-2</span>
The correct answer is 10x - 4. Hope this helps!!
Answer:
Any equation of the line that is different from y=x is the solution to the problem.
Step-by-step explanation:
step 1
Find the slope of the line that passes through the points (1, 1) and (5, 5)
m=(5-1)/(5-1)=1
step 2
Find the equation of the line into slope point form
y-y1=m(x-x1)
we have m=1
(x1,y1)=(1,1)
substitute
y-1=(1)(x-1)
y=x-1+1
y=x
therefore
Any equation of the line that is different from y=x is the solution to the problem.
