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bulgar [2K]
3 years ago
11

A right pyramid with a square base has a base length

Mathematics
1 answer:
Nuetrik [128]3 years ago
8 0

Answer:

1/3 x^2(x+2) is the expression ...

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Mr West has a picture that is 4 inches wide and 7
Pepsi [2]

Answer:

Step-by-step explanation:

The ratio of new length 7 to the initial length 19 is 2.7

Therefore new width will be 2.7×4 which will be 10.9 or about 11 inches

6 0
3 years ago
Read 2 more answers
352, 345, 338, ...<br> Find the 43rd term.
Artemon [7]

Answer:

Step-by-step explanation:

first term = a = 352

Common difference = d = second term - first term

                                  = 345 - 352

                                   = (-7)

nth term = a + (n-1)*d

43rd term = 352 + (43-1)*(-7)

                 = 352 + 42 *(-7)

                  = 352 - 294

                  = 58

3 0
3 years ago
Find limit as x approaches 2 from the left of the quotient of the absolute value of the quantity x minus 2, and the quantity x m
Molodets [167]

Answer:

\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

Step-by-step explanation:

We want to find \lim_{x \to 2^-} \frac{|x-2|}{x-2}.

By definition:

|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1).

The limit of a constant is the constant.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

8 0
3 years ago
Please help asap need help fast
OlgaM077 [116]
The answer is that they all are Latin Jazz artists
7 0
3 years ago
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How does Roosevelt use appeals to convince the
Bad White [126]

Answer:

Roosevelt appeals to the logic of the audience by noting that the interests of the people are not considered in a one-party government.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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