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monitta
4 years ago
11

At 6 A.M the temperature in Hibbing, Minnesota, was -35° F. If the temperature had risen 29° by 2 P.M and

Mathematics
1 answer:
seropon [69]4 years ago
6 0

Answer:

-12°F

Step-by-step explanation:

2 P.M

-35° F + 29° F= -6° F

The temperature had risen by 29°F meaning it went up by 29.

Adding negative 35 and positive 29 is the same as subtracting 35 from 29.

29 - 35 = -6

6 P.M

-6° F - 18°F  = -12°F

The temperature had fallen by 18°F meaning it went down by 18°F.

p.s don't forget the label °F

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5 0
3 years ago
Rectangle EFGH is similar to rectangle JKLM. Which proportion can be used to
Dominik [7]

*See attached picture for the diagrams being referred to

Answer:

C. ⁵/12= ²/x

Step-by-step Explanation:

Given that rectangle EFGH is similar to rectangle JKLM, it means the corresponding sides of both rectangles are similar, and as such the ratios if the corresponding sides of rectangle EFGH and rectangle JKLM would be equal.

Thus, EF/JK = FG/KL

Since, EF = 5; JK = 12; FG = 2; and KL= x, therefore, the proportion to use in finding x would be:

⁵/12= ²/x

6 0
3 years ago
Drag each label to the correct location on the graph. Not all labels will be used.
mamaluj [8]

Answer:

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4 0
3 years ago
A water jug holds 8 quarts of water. The jug is shared evenly between 4 people. How many cups of water does each person get?
Elanso [62]
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6 0
3 years ago
A company manufactures and sells x television sets per month. The monthly cost and price-demand equations are
skelet666 [1.2K]

A) The maximum revenue is 450000$

B) The maximum profit is 216000$ when 2400 sets are manufactured and sold for 180$ each

C) When each set is taxed at ​$55​, the maximum profit is 99125$ when 1850 sets are manufactured and sold for 207.5$ each.

A)p(x)=300−(x/20​),

revenue R(x)=p*x

revenue R(x)=300x -(x2/20)

for maximum revenue dR/dx =0 ,

=>300-(2x/20)=0

=>x/10=300

=>x=3000

maximum revenue = R(3000)=300*3000 -(30002/20)

maximum revenue = R(3000)=450000$

B) profit =revenue -cost

profit P(x)=300x -(x2/20)-72000-60x

profit P(x)=240x -(x2/20)-72000

for maximum cost dP/dx =0

240 -(2x/20)=0

x=240*10

x=2400

p(2400)=300−(2400/20​)=180

profit P(2400)=240*2400 -(24002/20)-72000 =216000

The maximum profit is 216000$ when 2400 sets are manufactured and sold for 180$ each

c)

profit =revenue -cost -tax

profit P(x)=300x -(x2/20)-72000-60x-55x

profit P(x)=185x -(x2/20)-72000

for maximum cost dP/dx =0

185-(2x/20)=0

x=185*10

x=1850

p(1850)=300−(1850/20​)=207.5

profit P(1850)=185*1850 -(18502/20)-72000

profit P(1850)=99125$

When each set is taxed at ​$55​, the maximum profit is 99125$ when 1850 sets are manufactured and sold for 207.5$ each.

To know more about maximum profit check the below link:

brainly.com/question/4166660

#SPJ4

5 0
1 year ago
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