Question

-5g-3/h-3 + 7g+9/h-3 find the sum

Answer 1

-5g - 3/h-3 + 7g +9/h-3 = -5g + 7g -3/h-3 + 9/h-3 = 2g + (9 - 3)/(h-3) = 
= 2g + 6/(h-3) if we want it as one fraction it would be:

2g + 6/(h-3) = [2g(h-3) + 6]/(h-3) = $\frac{2gh - 6gh + 6}{h-3}$