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maria [59]
3 years ago
12

Write the expression below in standard form 3h-2(1+4h)

Mathematics
1 answer:
Slav-nsk [51]3 years ago
6 0

Answer:

Using the formula, write in standard form.

=

−

5

h

−

2

Step-by-step explanation:

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Please help me, Thank you :)
aliina [53]

Answer:

I am pretty sure its the first one

7 0
3 years ago
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What is the square root of 5 plus the square root of 5​
Charra [1.4K]

Answer:

That would be approximately 4.47.

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3 years ago
Which expression is not equivalent to Negative 3 x minus one-half 4 y? 2 y minus 5 x minus one-half 2 y 2 x Negative 2 x minus o
Alona [7]

Answer:

The wrt=itten expressions are too difficult to interpret properly.  I did my best but I don't see any of the answers as equivalent to <u>-3x - 2y, so please check my interpretations of the answer options.</u>

Step-by-step explanation:

"Negative 3 x minus one-half 4 y"

-3x- (1/2)4y

<u>or -3x - 2y</u>

<u>=====</u>

The answer options are too garbled for me to make sense of them.  Are they:

1.  2 y minus 5 x minus one-half 2 y  :  2y -5x - (1/2)2y; <u>y -5x</u>  ?

2.  2 x Negative 2 x minus one-half 6 y :  2(-2x)- (1/2)6y; <u>-4x - 3y</u>  ?

3.  3 x Negative 3 x minus three-fourths 4 y :  3x(-3x) - (3/4)4y;  <u>-9x -3y</u>  ?

4.   one-fourth Negative 3 y minus three-fourths 7 y one-fourth minus 3 x:

     (1/4)(-3y) - (3/4)7y - (1/4)(-3x);  -(3/4)y -(21/4)y + (3/4)x; -(24/4)y +         (3/4)x;  ?

     

I don't see any of the answers as equivalent to <u>-3x - 2y, so please check my interpretations of the answer options.</u>

8 0
2 years ago
Read 2 more answers
Whats an equation of a line thwt passes through the points (5,2) and (3,2)
Otrada [13]
2-2=0
5-3=2

so the answer is o over 2 aka 0/2
7 0
3 years ago
What is the inverse of the function
Evgesh-ka [11]

Answer:

A

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = \frac{19}{x^3} ( multiply both sides by x³ )

x³y = 19 ( divide both sides by y )

x³ = \frac{19}{y} ( take the cube root of both sides )

x = \sqrt[3]{\frac{19}{y} }

Change y back into terms of x, then

f^{-1} (x) = \sqrt[3]{\frac{19}{x} } = \frac{\sqrt[3]{19} }{\sqrt[3]{x} } → A

6 0
3 years ago
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