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bagirrra123 [75]
3 years ago
9

A pound of coffee beans yields 60 cups of coffee (4 cups = 1 qt). how many milliliters of coffee can be obtained from 1.0 g of c

offee beans?
Mathematics
1 answer:
kari74 [83]3 years ago
5 0
We can easily convert grams to pounds and find that 1 g of coffee beans is 0.00220462 pounds. Now we can multiply that value with 60 cups to find how many cups it makes.

We find that it makes 0.1322772 cups.

Then we know that 236.588 milliliters are in a cup. We multiply the value of the coffee available with 1 g of coffee beans (in cups - of course) and get the value the question asked :

0.1322772 * 236.588 milliliters

The answer is 31.2951981936 milliliters!

Hope this helps!

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Water is added or drained from a tank each day. The first day, 910 of a gallon is added to the empty tank. The second day, 710 o
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Answer:

The quantity of water in the tank after 15 days is 1610.0 gallons OR 1.61 × 10³ gallons.

Step-by-step explanation:

The amount of water in the tank after 15 days is given by the series

910+(−710)+810+(−610)+⋯+310+(−110)+210

From the series, we can observe that, if water is added for a particular day then water will be drained the following day.

Also, for a day when water is to be added, the quantity to be added will be 100 gallon lesser than the quantity that was last added. Likewise, for a day when water is to be drained, the quantity to be drained will be 100 gallons lesser than the quantity that was last drained.

Hence, we can complete the series thus:

910+(−710)+810+(−610)+710(-510)+610(-410)+510(-310)+410(-210)+310+(−110)+210

To evaluate this, we  get

910-710+810-610+710-510+610-410+510-310+410-210+310-110+210

= 1610.0 gallons

Hence, the quantity of water in the tank after 15 days is 1610 gallons OR 1.61 × 10³ gallons.

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3 years ago
A baseball player throws a ball from second base to home plate. How far does the player throw the ball?
Fynjy0 [20]

Answer:

The player throws 127.3 ft from second base to home plate.

Step-by-step explanation:

Given:

Distance from home to first base = 90 ft

Distance from first base to second base = 90 ft

We need to find the distance from second base to home.

Solution:

Now we can assume the complete scenario to be formed as a right angled triangle with two sides given and to find the third side.

Now by using Pythagoras theorem which states that;

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framing in equation form we get;

distance from second base to home = \sqrt{90^2+90^2}= 127.27 \ ft

Rounding to nearest tent we get;

distance from second base to home = 127.3 ft

Hence The player throws 127.3 ft from second base to home plate.

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