For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
For question number 2:To find the maximal height, just simply substitute t = 11.5 into the quadratic equation. The answer would be 22.9.
For question number 3:H(t) = 0, or, which is the same as -16t^2 + 368t = 0.Factor the left side to get -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.
Answer:
63
Step-by-step explanation:
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Answer:
The student's current average score will be 69.2
Step-by-step explanation:
Let first test be TEST A: which is 20 of total and secures 62
Let second test be TEST B: which is 20 of the total marks and has secured 83.
Let third test be TEST C: which is 20 of total and has secured 91.
And now the TEST D which is 25 of total and has secured 88.
Therefore, by multipying across
= 12.4
= 16.6
= 18.2
=22
Now, by adding the scores to get the average score
We get, 69.2.
0.06 times 96 equals 5.76
