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vagabundo [1.1K]
3 years ago
7

Pleaseeeeeeeeess help meeee ​

Mathematics
1 answer:
stich3 [128]3 years ago
6 0

Answer:

7 and 1/8 is the correct answer

Step-by-step explanation:

Multiply the fractions I think.

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SOMEBODY PLEASE HELP ME!!
notsponge [240]

Answer:

60 square units; 40 units

Step-by-step explanation:

to find the missing side you use the pythagorean theorem

a^2 + b^2 = c^2

8^2 + b^2 = 17^2

64 + b^2 = 289

b^2 = 225

b = 15

area is l*h*1/2

15 * 8 * 1/2 = 60 square units

perimeter is adding them all

15 + 8 + 17 = 40 units

8 0
2 years ago
G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =
Svetach [21]
Presumably you should be doing this using calculus methods, namely computing the surface integral along \mathbf r(u,v).

But since \mathbf r(u,v) describes a sphere, we can simply recall that the surface area of a sphere of radius a is 4\pi a^2.

In calculus terms, we would first find an expression for the surface element, which is given by

\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv

\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k
\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j
\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k
\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u

So the area of the surface is

\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u
=-2\pi a^2(\cos\pi-\cos 0)
=-2\pi a^2(-1-1)
=4\pi a^2

as expected.
6 0
3 years ago
Which words in the salutation should be capitalized? dear aunt mary, Choose all answers that are correct. A. Dear B. Aunt C. Mar
andreyandreev [35.5K]
Everything should be capitalized. If "dear" is the beginning of a sentence, it should be capitalized. "aunt" and "mary" are a name so they should be capitalized too.
4 0
3 years ago
Read 2 more answers
X an y are proportional. What is the missing value in the table <br>​
Leto [7]

Answer:

X+y

Step-by-step explanation:

6 0
3 years ago
Is X-13=x+1 true or false
Black_prince [1.1K]

Answer: FALSE.

Step-by-step explanation:

Given the following equation provided in the exercise:

x-13=x+1

You need to solve for the variable "x".

In order to solve for "x" you can folllow the steps shown below:

1. You must apply the Addition property of equality and add 13 to both sides of the equation. Then:

x-13+(13)=x+1+(13)\\\\x=x+14

2. Finally you need to apply the Subtraction property of equality and subtract "x" from both sides of the equation. So you get:

x-(x)=x+14-(x)\\\\0=14\ (FALSE)

Therefore, as you can observe, the given equation has no solutions.

3 0
3 years ago
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