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BigorU [14]
3 years ago
13

" class="latex-formula">
Mathematics
1 answer:
const2013 [10]3 years ago
5 0

Hi there! :)

<u>Answer:</u>

x = -2


Step-by-step explanation:

<u>5</u> - 3x = 11

Subtract "5" from each side of the equation → 11 - 5 = 6

<u>-3</u>x = 6

Divide each side of the equation by "-3" → 6 ÷ -3 = -2

<u>x = -2</u>


There you go! I really hope this helped, if there's anything just let me know! :)

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Using substitution how do u solve <br> 3y+2x=6<br> and 5y-2x=10
Sergeu [11.5K]
<span>3y+2x=6
5y-2x=10
--------------add
8y = 16
y = 2

</span>3y+2x=6
3(2)+2x=6
6 + 2x = 6
2x = 0
x = 0

answer: x = 0 and y = 2 or (0,2)
7 0
3 years ago
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Find each value of the five-number summary for this set of data. [Note: Type your answers as numbers. Do not round.] 46, 19, 38,
frozen [14]

Answer:

Maximum : 51

Minimum: 12

Median: 38

Lower quartile: 19

Upper quartile: 46

Step-by-step explanation:

To answer this question, we first order the data from largest to smallest:

46, 19, 38, 27, 12, 38, 51

12, 19, 27, 38, 38, 46, 51

It can be seen that the maximum value is:

51

The minimum value is

12

Let's call N the amount of data.

To calculate the quartiles we use the following formula:

Q_1 = X_{\frac{1}{4}(N + 1)}

So:

Q_1 = X_{\frac{1}{4}(7 + 1)}

Q_1 = X_2

Where X_2 is the data number 2.

Q1 = 19

As the number of data is imapar, then, the median is the central data:

12, 19, 27, {38}, 38, 46, 51

Median = 38

Finally:

Q_3 = X_ {\frac{3}{4}(n + 1)}\\\\Q_3 = X_ {6}

Where X_6 represents the data number 6

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4 0
3 years ago
The shark are fed three times a day during the morning feeding 2/15 of a ton. During the afternoon feeding the weight of fish fe
UNO [17]

Answer:

The shark are fed \frac16 \ ton of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = \frac{2}{15}\ ton

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = \frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton

Total fish fed in whole day = \frac12 \ ton

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = \frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}

Now we will use LCM for making the denominator common we get;

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Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = \frac{3-2}{6}=\frac16 \ ton

Hence The shark are fed \frac16 \ ton of fish during the night.

3 0
3 years ago
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aev [14]
The answer would be 16.80
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Pie
36÷0.45=80
There are 80 beads altogether
5 0
3 years ago
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