<span>x(2x-2)
distribute the x to get our answer of
2x^2-2x
</span>
Q.34

The infinite geometric series is converges if |r| < 1.
We have r =1.002 > 1, therefore our infinite geometric series is Diverges
Answer: c. Diverges, sum not exist.
Q.35

The infinite geometric series is converges if |r| < 1.
We have r = 4/5 < 1, therefore our infinite geometric series is converges.
The sum S of an infinite geometric series with |r| < 1 is given by the formula :

We have:

substitute:

Answer: c. Converges, -25.
Answer:
ok l got it
Step-by-step explanation: