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Vera_Pavlovna [14]
3 years ago
10

Use the integral test to determine whether the infinite series is convergent. ∑n=1∞n−13 fill in the corresponding integrand and

the value of the improper integral. enter inf for ∞, -inf for −∞, and dne if the limit does not exist. compare with ∫∞1 dx = by the integral test, the infinite series ∑n=1∞n−13
a. converges
b. diverges
Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0
Looks like the series is

\displaystyle\sum_{n=1}^\infty n^{-13}

We have

\displaystyle\sum_{n=1}^\infty\frac1{n^{13}}
\displaystyle=-\frac1{12x^{12}}\bigg|_{x=1}^{x\to\infty}
\displaystyle=-\frac1{12}\left(\lim_{x\to\infty}\frac1{x^{12}}-1\right)=\frac1{12}

Therefore the sum converges, since its value is smaller than \dfrac1{12}.
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