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Leto [7]
3 years ago
6

Math question quadratics

Mathematics
2 answers:
denpristay [2]3 years ago
4 0

Answer: The length and width are 50 and 30 meters (or 30 and 50 meters).

Step-by-step explanation:

To solve this question, we can represent variables for the length and width in two equations.

2l + 2w = 160\\\\l * w= 1500

To solve for one of the variables, you'll have to substitute one of the variables, so solve for one of them:

2l = 160 - 2w\\l = 80 - w

(80-w)*w=1500\\\\-w^2 + 80w - 1500 = 0\\\\w^2 - 80w + 1500 = 0

Now, we have a standard quadratic equation that we can factor. When factoring, you'll get this:

(w-50)(w-30) = 0

This tells us that the width could be either 50 or 30.

Substitute 50 into one of the equations to find the length:

2 (l) + 100 = 160

l = 30.

The length and width are 50 and 30 meters (or 30 and 50 meters).

steposvetlana [31]3 years ago
3 0

Answer:

            (y1, y2)= (30,50)

            (x1, x2)= (50,30)

If x is the length, it would be 50 m, y (width) would be 30 m

It depends on the way you determine x and y

Step-by-step explanation:

The perimeter of the pool:

  (x+y)*2= 160

So the total length and width of the pool is:

   x+y = 80 (1)

The area of the pool:

   xy= 1500 (2)

(1), (2) =) x+y=80

             xy= 1500

         =) y= 80-x

             x (80-x) =1500

         =) y= 80-x

            80x -x² = 1500

         =) y= 80 -x

             x² - 80x +1500=0

         =) y1= 80- 50               y2= 80-30

             (x1, x2)= (50,30)

         =) (y1, y2)= (30,50)

             (x1, x2)= (50,30)

   

         

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2, 8, 32, 128,

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8/2= 4

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3 years ago
At what point on the parabola y = 3x^2 + 2x is the tangent line parallel to the line<br> y = 10x −2?
oksian1 [2.3K]

Answer:

( \frac{4}{3} , 8 )

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 10x - 2 ← is in slope- intercept form

with slope m = 10

Parallel lines have equal slopes

then the tangent to the parabola with a slope of 10 is required.

the slope of the tangent at any point on the parabola is \frac{dy}{dx}

differentiate each term using the power rule

\frac{d}{dx} (ax^{n} ) = nax^{n-1} , then

\frac{dy}{dx} = 6x + 2

equating this to 10 gives

6x + 2 = 10 ( subtract 2 from both sides )

6x = 8 ( divide both sides by 6 )

x = \frac{8}{6} = \frac{4}{3}

substitute this value into the equation of the parabola for corresponding y- coordinate.

y = 3(\frac{4}{3} )² + 2

   = (3 × \frac{16}{9} ) + 2

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2 years ago
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VikaD [51]

(x^{2} + 4)(x^{2} - 4)

To solve this question you must FOIL (First, Outside, Inside, Last) like so

First:

(x^2 + 4)(x^2 - 4)

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x^4

Outside:

(x^2 + 4)(x^2 - 4)

x^2 * -4

-4x^2

Inside:

(x^2 + 4)(x^2 - 4)

4 * x^2

4x^2

Last:

(x^2 + 4)(x^2 - 4)

4 * -4

-16

Now combine all the products of the FOIL together like so...

x^4 - 4x^2 +4x^2 - 16

Combine like terms:

x^4 - 4x^2 +4x^2 - 16

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3 years ago
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Vitek1552 [10]

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Step-by-step explanation:

1st method is the thousandths place larger or smaller

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2nd method

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Since the number recieved is positive this means .513 is larger

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