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Leni [432]
3 years ago
8

Which function is increasing?? :)

Mathematics
1 answer:
exis [7]3 years ago
7 0

Answer:

\large\boxed{B.\ f(x)=4^x}

Step-by-step explanation:

Exponential function f(x)=(a)^x is

increasing if a > 1\to a\in(1,\ \infty)

decreasing if 0 < a < 1\to a\in(0,\ 1)

A.\ f(x)=\left(\dfrac{1}{4}\right)^x\to a=\dfrac{1}{4}\in(0,\ 1)\to\text{decreasing}\\\\B.\ f(x)=4^x\to a=4\in(1,\ \infty)\to\text{increasing}\\\\C.\ f(x)=(0.4)^x\to a=0.4\in(0,\ 1)\to\text{decreasing}\\\\D.\ f(x)=\left(\dfrac{1}{2}\right)^x\to a=\dfrac{1}{2}\in(0,\ 1)\to\text{decreasing}

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The markup is 8%, meaning it costs 8% more.
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Therefore, the markup is 108% of $12.
If we multiply 12 by 108% (1.08), we will get our answer of $12.96
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Answer:

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Step-by-step explanation:

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