I believe number 14 is asking where the points are located. If so D (-3,-3) E(-3,-2) G(4,1) F(4,2)
For perpendicular lines, m1m2 = -1 or m2 = -1/m1; where m1 and m2 are the slopes of the lines.
Here line 1 is 2x - y - 7 = 0
y = 2x - 7; Hence m1 = 2
m2 = -1/2
Required equation y - y1 = m2(x - x1)
y - (-1) = -1/2(x - 4)
y + 1 = -1/2x + 2
y = -1/2x + 2 - 1
y = -1/2x + 1
(-0.2,1.2)
substitute 3x+2 for y and set them equal to eachother then plug in x for y
Answer:
d. 11:15
Step-by-step explanation:
1) officer1: distance 75 miles, velocity 60mil/h; officer2: distance 25 miles, velocity 55mil/h;
2) time, which is spent officer1 is: 75/60=1.25[h]=75 [min]. If the officer1 leaves his office at 10:00, the arrival time is 11:15;
3) time which is spent officer2 is: 25/55=5/11[h]≈27[min]. The arrival time is 10:27.
4) finally, the both officers are in the required location at 11:15.
