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Kaylis [27]
3 years ago
14

Masha biked 20km 20 minutes faster than Dasha biked 20km. Find the speed of each cyclist if one biked 2km/h faster than the othe

r.
Mathematics
1 answer:
motikmotik3 years ago
3 0

Answer:

  • 12 km/h and 10 km/h

Step-by-step explanation:

Let the speed of Masha = s, speed of Dasha = d

  • Distance = 20 km
  • Time difference = 20 min = 1/3 hr
  • Speed difference  = 2 km/h

<u>As per above info we get following equations:</u>

  • s = d + 2
  • 20/s + 1/3 = 20/d

<u>Substitute s and solve for d:</u>

  • 20/(d + 2) + 1/3 = 20/d

<u>Get rid of fraction by multiplying all terms by 3d(d + 2):</u>

  • 60d + d(d + 2) = 60(d + 2)
  • 60d + d² + 2d = 60d + 120
  • d² + 2d = 120
  • d² + 2d + 1 = 121
  • (d + 1)² = 11²
  • d + 1 = 11
  • d = 10

<u>Find s:</u>

  • s = 10 + 2 = 12

<u>The answer is</u>

  • Masha's speed 12 km/h and Dasha's speed 10 km/h
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Diano4ka-milaya [45]

Answer:

x = 1

y = 3

Step-by-step explanation:

<h2><em><u>Substitution Method</u></em><em><u>:</u></em></h2>

Step 1:

Name The Equation

4x + y = 7 ...(1)

3x + 2y = 9 ...(2)

Step 2:

From Equation (1) we get,

4x = 7 - y

i.e.,

x = 7 - y/4

Step 3:

Substitute the value of <em><u>x = 7 - y/4</u></em> in equation (2)

i.e.,

3(7 - y/4) + 2y = 9

21 - 3y/4 + 2y = 9

21 - 3y + 8y/4 = 9

21 - 3y + 8y = 9 * 4

21 + 5y = 36

5y = 36 - 21

5y = 15

y = 15/5

<em><u>y = 3</u></em>

Step 4:

Substitute the value of <em><u>y = 3</u></em> in equation (1)

4x + y = 7

i.e.,

4x + (3) = 7

4x + 3 = 7

4x = 7 - 4

4x = 4

x = 4/4

<em><u>x = 1</u></em>

<h2><em><u>Verification</u></em><em><u>:</u></em><em><u> </u></em></h2>

4x + y = 7 i.e., <em>4(1) + (3) = 7</em>

3x + 2y = 9 i.e., <em><u>3(1) + 2(3) = 9</u></em>

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Step-by-step explanation:

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Step-by-step explanation:

(1/6)(15a+20b)

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Larry the librarian and Courtney the lawyer are having a debate. Larry contends that the library is bigger than the courthouse i
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Step-by-step explanation:

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