Answer:
It is not. Also use ^2 to represent squaring a number.
Step-by-step explanation:
First, USE ^2 FOR SQUARED
It is not correct.
The standard equation of a circle is (x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius.
In your question the center is (-2,3) and the radius is the length of the line segment from the center to any pointon the circle. nd hey, it tells us a point on the circle is (-2,6).
Let's take it one part at a time. we know h and k so let's plug them in.
(x-h)^2 + (y-k)^2
(x-(-2))^2 + (y-3)^2
(x+2)^2 + (y-3)^2
now r is the length of the line segment from (-2,3) and (-2,6). To get from (-2,3) to (-2,6) hopefully it is pretty obvious you just move up (so int he y direction) 3 spaces. this makes r = 3. int he formula we want r^2 and that is 9. The result is that the circle has a formula of:
(x-h)^2 + (y-k)^2 = r^2
(x+2)^2 + (y-3)^2 = 9
The formula Juanita got is actually a hyperbola.
