Ask question

Ask question

All categories

kondor19780726 [428]

3 years ago

7

10 POINTSHow do you find the absolute deviation of a data

1 answer:

zzz [600]3 years ago

5 0

Answer:

To find the mean absolute deviation of the data, start by finding the mean of the data set. Find the sum of the data values, and divide the sum by the number of data values. Find the absolute value of the difference between each data value and the mean: |data value – mean|.

I hope this helpsssssssssss :D

You might be interested in

What is the value of x

viktelen [127]

Answer:

X=14

Step-by-step explanation:

6 0

3 years ago

Simplify -2.3f+0.9f-14-4

Setler [38]

Answer:

The Answer would be 1.4f-18

Step-by-step explanation:

-2.3f+0.9f-14-4

then you do

-1.4f-14-4

Then u would get 1.4f-18.

7 0

3 years ago

Read 2 more answers

A dozen plain hats cost 3.60,what is the unit rate of a hat?

deff fn [24]

I think the answer should be 12.

7 0

3 years ago

Read 2 more answers

Show that the following functions are probability density functions for some value of k and determine k. Then, determine the mea

lord [1]

Answer:

a) 17.5

b) 15.6

c) 13.3

d) 21.51

Step-by-step explanation:

The given function is equal to:

f(x)=kx^2

where

$\int\limits^y_0 {kx^{2} } \, =1$

where y=23

Clearing k=0.00025

a) $Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.00025x^{2} } \, dx =17.5$

b) $Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2}f(x) } \, dx-17.5^{2} =\int\limits^y_0 {x^{2} *0.00025x^{2} } \, dx -17.5^{2} =321.82-306.25=15.6$

c) The function is equal to:

f(x)=k(1+2x)

$\int\limits^y_0 {k(1+2x)} \, =1$

where y=20

k=0.0024

$Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.0024(1+2x)} \, dx =13.3$

d) $Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2} f(x)} \, dx -13.3^{2}=\int\limits^y_0 {x^{2} *0.0024(1+2x)} \, dx-13.3^{2} =198.4-176.89=21.51$

8 0

3 years ago

In the triangle below, which equation can<br> be used to solve for x?

aivan3 [116]

The answer is B x=13sin75/sin50

4 0

2 years ago