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3 years ago

Given f(x) and g(x) = f(x) k, look at the graph below and determine the value of k.

Mathematics

2 answers:

alexgriva [62]3 years ago

5 0

Find out how many units higher g(x) is compared to f(x).

g(x) is 3 units higher than f(x)

Since the graph is 3 units higher, the value of k is 3.

K = 3

Firdavs [7]3 years ago

3 0

Answer:

k = 3

Step-by-step explanation:

g(x) is 3 units higher than f(x), so k = 3.

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topjm [15]

The answer is B. I hope this helps

7 0

3 years ago

Let f be defined by the function f(x) = 1/(x^2+9)

riadik2000 [5.3K]

(a)

$\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}$

Substitute x = 3 tan(t ) and dx = 3 sec²(t ) dt :

$\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt$

$=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}$

(b) The series

$\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}$

converges by comparison to the convergent p-series,

$\displaystyle\sum_{n=3}^\infty\frac1{n^2}$

$\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}$

converges absolutely, since

$\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}$

That is, ∑ (-1)ⁿ (n ² + 9)/eⁿ converges absolutely because ∑ |(-1)ⁿ (n ² + 9)/eⁿ| = ∑ (n ² + 9)/eⁿ in turn converges by comparison to a geometric series.

5 0

3 years ago

AB = 10 and AC = 2 StartRoot 10 EndRoot. What is the perimeter of △ABC?

WITCHER [35]

Answer:

20 + 2 units

Step-by-step explanation:

because the perimeter of ∆ ABC is the answer 20 + 2

4 0

2 years ago

What are the X and Y intercepts of y= -2(x-4)2 +3

kari74 [83]

Answer: x-intercepts are ( 2.775,0) and (5.225,0)

And y-intercept is (0,-29)

Step-by-step explanation:

Here the given equation is,

$y = -2(x-4)^2+3$

For x-intercept, y = 0,

Put y = 0 in the above equation of parabola,

We get, $-2(x-4)^2 + 3 = 0$

$-2(x^2+16+8x) + 3 = 0$

$-2x^2-32-16x + 3 = 0$

$-2x^2-16x -29 = 0$

By solving this equation,

We get, x = 2.775 or x = 5.225

Therefore, x-intercept of the given parabola are (2.775, 0) and (5.225,0)

Now, for y-intercept, x = 0

By putting x = 0 in the given equation of parabola,

We get, y = -29

Thus, y-intercept of the given parabola = (0,-29)

4 0

3 years ago

PLZZZ CHECK ME Is this correct, if not please help me.

Gwar [14]

Hello! For this question, you solve using order of operations, which you probably already have remembered as PEMDAS. Anytime a number is raised to the 0 power, that is equivalent to 1. 0.5^0 is 1. 250 * 1 is 250. x = 0 gives us the answer of 250. Now, let's solve for the number by the second power. 0.5² is 0.25. 250 * 0.25 is 62.5. x² gives us 62.5. Now, let's subtract the two numbers together. 250 - 62.5 is 187.5. Because the number is decreasing, the slope is negative, so the answer is -187.5. Your answer is correct.

5 0

3 years ago