Remember these two combinations: logab=loga+logb, log(a/b)=loga-logb
3logx=logx^3
(1/2)log(x+2)=log(x+2)^(1/2)
2log(z-4)=log(z-4)^2
so the given expression can be combined into log{[(x^3)(z-4)^2]/(x+2)^(1/2)}
I remember doing this one and its c
Answer:
24
Step-by-step explanation:
substitute the given values for a and z into the expression
- 3az
= - 3(- 2)(4) = 6 × 4 = 24
