If you draw only 25 balls, you could draw the 25 odd-numbered balls. However, there will then be no odd-numbered balls left, so when you draw two more you will be guaranteed to get two even-numbered balls. Thus, the minimum is 25+2=27 balls.
The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using

Substitute the known values in the above equation

Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Answer:
2:9 4:8
8:3 24:6
9:7 3:2
18:15 6:6
18:12 12:16
10:40 5:9
12:16 6:7
12:36 12:18
45:15 4:5
those in bold are the answer
Answer:
ANSWER: ADC=82
bda = 144
(7x+34)+(9x+46)=144
16x+80=144
16x=64
x=4
9(4)+46=82
adc=82
Step-by-step explanation:
Convert them to comparable thingummys
convert to fraction
percent means parts out of 100
30%=30/100=3/10
3/10 vvs 1/3
make bottom number 30
3/10 times 3/3=9/30
1/3 times 10/10=10/30
10/30>9/30
1/3 is bigger