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2 years ago

What is the slope of a line perpendicular to line B?

Mathematics

2 answers:

dusya [7]2 years ago

7 0

The slope of a line perpendicular to line B would -1/2. This is because the slope of line B is 2 and whenever you’re finding a perpendicular slope you find the reciprocal of the original one. So the reciprocal of 2 is -1/2

aliina [53]2 years ago

5 0

Answer:

m = -2/5

Step-by-step explanation:

The first thing we need to do is find the slope of line B.

m = (y2 - y1) / (x2 - x1)

m = (5 - (-5)) / (3 - (-1))

m = 10 / 4

m = 2 1/2 or 5/2

The slope of a line perpendicular to line B will be the negative reciprocal of 5/2. Just flip the numerator and the denominator and add a minus sign:

5/2 → -2/5

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Haz la sustitución:

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Sustituye:

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Sustituye:

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Podemos hacer que esto se vea un poco mejor:

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3 years ago

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

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Multiply both sides by a:

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Here we have:

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So we are solving

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Distribute:

3k-2=-k+6

Add k on both sides:

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Divide both sides by 4:

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Let's check:

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$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

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Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

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Answer:

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Step-by-step explanation:

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