2 years ago

Please help and thank you

Mathematics

1 answer:

stira [4]2 years ago

3 0

B.

The points are (-4,-2)

The -4 would be positive because you make the h in (x-h) opposite of the real sign.

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PLEASE HELP SOLVE!!!!!!!! -72 < 8m < -32 -5r > -15 or r + 5 > 14

denis23 [38]

That's the first one

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3 years ago

Pls give an explanation w your answer

Shalnov [3]

$a^{\frac{1}{n}}=\sqrt[n]{a}\\\\\left(a^n\right)^m=a^{n\cdot m}\\\\a^n\cdot a^m=a^{n+m}$
therefore
$64^\frac{1}{4}=\left(2^6\right)^\frac{1}{4}=2^{6\cdot\frac{1}{4}}\\\\=2^\frac{6}{4}=2^{1\frac{2}{4}}=2^{1+\frac{2}{4}}=2\cdot2^\frac{2}{4}\\\\=2\sqrt[4]{2^2}=2\sqrt[4]4$
Other method:
$64^\frac{1}{4}=\sqrt[4]{64}=\sqrt[4]{16\cdot4}=\sqrt[4]{16}\cdot\sqrt[4]4=2\sqrt[4]4$

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