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3 years ago

Can someone please help me with this???

Mathematics

1 answer:

Rom4ik [11]3 years ago

3 0

The point would be (-5, 6). I hope I helped.

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Long division 5th grade I’m sorry if I’m asking a lot but I’m really new to this

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2 years ago

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The graph of F(x) shown below resembles the graph of G(x) = x4, but it has

DerKrebs [107]

Using translation concepts, the equation of F(x) is:

A. $F(x) = \frac{1}{3}x^4 - 2$

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

The parent function is:

$G(x) = x^4$

For function F(x), we have that:

It was shifted down 2 units, hence F(x) = G(x) - 2.

It was vertically compressed by a factor of 3, hence $F(x) = \frac{1}{3}G(x) - 2$

Then the equation is:

A. $F(x) = \frac{1}{3}x^4 - 2$

More can be learned about translation concepts at brainly.com/question/28098112

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1 year ago

The vertices of two rectangles are A(−5,−1),B(−1,−1),C(−1,−4),D(−5,−4) and W(1,6),X(7,6),Y(7,−2),Z(1,−2). Compare the perimeters

valkas [14]

The two rectangles are not similar. actually WXYZ is not a rectangle at all. it is a polygon but not a rectangle. hope the visual helps..

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3 years ago

F(t)=t^2+19t+60<br> What are the zeros of the function and what is the vertex of the parabola?

SVEN [57.7K]

Answer: $-4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

Step-by-step explanation:

Given

Function is $F(t)=t^2+19+60$

Zeroes of the function are

$t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15$

Using completing the square method

$y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

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3 years ago