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3 years ago

-2 = 7+3v Solve for v

Mathematics

2 answers:

Digiron [165]3 years ago

8 0

-3v = 7+2. -3v=9. V=9/3. =-3. I think this is the answer Hope it helps

Amiraneli [1.4K]3 years ago

8 0

Answer:

$- 2 - 7 = 3v$

or,

$- 9 = 3v$

or,

$- 9 \div 3 = v$

or,

$-3 = v$

or,

$v = - 3$

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alexdok [17]

Answer:

$f(x)=x+\dfrac{x^{3}}{3}+\dfrac{2x^{4}}{3}....$

Approximate error = 0.4426

Step-by-step explanation:

f(x)=tanx, a=0

Maclaurin series formula used is given below

$f(x)=\sum_{n=0}^{\infty}\dfrac{f^{(n)}(0)x^{n}}{n!}=f(0)+f'(0)x+\dfrac{f''(0)}{2!}x^{2}+\dfrac{f'''(0)}{3!}x^{3}+....$

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Hence, the Taylor series for f(x)=tanx is given by

$f(x)=x+\dfrac{x^{3}}{3}+\dfrac{2x^{4}}{3}....$

Maclaurin series upper bound error formula used is given as

R_n(x)=|f(x)-T_n(x)|

R_3(x)=|tanx-T_3(x)|

$R_3(x)=|tanx-x-\dfrac{x^{3}}{3}-\dfrac{2x^{4}}{3}|$

Plugging this value x=1

$R_3(x)=|tan(1)-1-\dfrac{1}{3}-\dfrac{2}{3}|\\$

R_3(x)=|1.5574-1-0.333-0.666|

R_3(x)=|-0.4426|=0.4426

Hence, upper bound on the error approximation

tan(1)=0.4426

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3 years ago

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Answer:

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Step-by-step explanation:

Use similar triangles and laws of proportions.

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