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schepotkina [342]
3 years ago
9

What is the area of this parallelogram? 10.35 cm² 12.5 cm² 20.25 cm² 30.6 cm² Parallelogram A B C D is composed of a square and

two triangles. The square has a length and height of 4.5 centimeters each. There are two identical triangles. Each triangle has a base of 2.3 centimeters and a height of 4.5 centimeters.

Mathematics
2 answers:
nydimaria [60]3 years ago
8 0

Answer:

30.6 cm²

Step-by-step explanation:

Dividing the parallelogram into 2 geometry shapes:

Square

2 Right angle triangles

Area of a square, As = length^2

= 4.5^2

= 20.25 cm^2

Area of a right angle triangle, At = 1/2 × base × height

= 1/2 × 2.3 × 4.5

= 5.175 cm^2

Sinve there are 2 right angle triangle,

At = 2 × 5.175

= 10.35 cm^2

Total area of the parallelogram, Ap = area of the square + area of the 2 right angle triangle

= 10.35 + 20.25

= 30.6 cm^2

Taya2010 [7]3 years ago
5 0

Answer:

30.6 cm²

Step-by-step explanation:

The area of the parallelogram is simply the sum of the areas of the component three shapes - the square and the two triangles.

Area of square = 4.5 cm × 4.5 cm = 20.25 cm²

Area of two triangles = 2 ×(1/2) × 2.3 cm × 4.5 cm = 10.35 cm²

Area of parallelogram =  20.25 cm² + 10.35 cm² = 30.6 cm²

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(3x^{2}y^{2}-3x^{2}y^{2})-2xy^{5}+3x^{4}y

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An urn contains 8 red chips, 10 green chips, and 2 white chips. A chip is drawn and replaced, and then a second chip is drawn.
Harlamova29_29 [7]

Answer:

(A) 0.04

(B) 0.25

(C) 0.40

Step-by-step explanation:

Let R = drawing a red chips, G = drawing green chips and W = drawing white chips.

Given:

R = 8, G = 10 and W = 2.

Total number of chips = 8 + 10 + 2 = 20

P(R) = \frac{8}{20}=\frac{2}{5}\\P(G)=  \frac{10}{20}=\frac{1}{2}\\P(W)=  \frac{2}{20}=\frac{1}{10}

As the chips are replaced after drawing the probability of selecting the second chip is independent of the probability of selecting the first chip.

(A)

Compute the probability of selecting a white chip on the first and a red on the second as follows:

P(1^{st}\ white\ chip, 2^{nd}\ red\ chip)=P(W)\times P(R)\\=\frac{1}{10}\times \frac{2}{5}\\ =\frac{1}{25} \\=0.04

Thus, the probability of selecting a white chip on the first and a red on the second is 0.04.

(B)

Compute the probability of selecting 2 green chips:

P(2\ Green\ chips)=P(G)\times P(G)\\=\frac{1}{2} \times\frac{1}{2}\\ =\frac{1}{4}\\ =0.25

Thus, the probability of selecting 2 green chips is 0.25.

(C)

Compute the conditional probability of selecting a red chip given the first chip drawn was white as follows:

P(2^{nd}\ red\ chip|1^{st}\ white\ chip)=\frac{P(2^{nd}\ red\ chip\ \cap 1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\=\frac{P(2^{nd}\ red\ chip)P(1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\= P(R)\\=\frac{2}{5}\\=0.40

Thus, the probability of selecting a red chip given the first chip drawn was white is 0.40.

6 0
3 years ago
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