A car travels along a straight road for 30 seconds starting at time t = 0. Its acceleration in ft/sec2 is given by the linear gr
aph below for the time interval [0, 30]. At t = 0, the velocity of the car is 0 and its position is 10. What is the total distance the car travels in this 30 second interval? Your must show your work but you may use your calculator to evaluate. Give 3 decimal places in your answer and include units.
I think I need to find the velocity equation then take the absolute value of the integral from 0 to 30, but I'm not sure how to find the velocity equation.
I think I need to find the velocity equation then take the absolute value of the integral from 0 to 30, but I'm not sure how to find the velocity equation.
1 answer:
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Answer:
The sales level that has only a 3% chance of being exceeded next year is $3.67 million.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
In millions of dollars,
Determine the sales level that has only a 3% chance of being exceeded next year.
This is the 100 - 3 = 97th percentile, which is X when Z has a pvalue of 0.97. So X when Z = 1.88.
The sales level that has only a 3% chance of being exceeded next year is $3.67 million.