For this, we will be using Triangle Angle Sum Theorem (all interior angles in a triangle add up to 180°) for Triangle BCD. Since Angle CBD and BDC are congruent to each other and Angle BDA, we can solve for those two angles to get that angle. Our equation will look like this:
Firstly, subtract 35 on both sides of the equation:
Next, divide both sides by 2 and your answer will be 72.5 = x.
Since Angle CBD and BDC are 72.5°, this means that Angle BDA is 72.5° as well.
Based on the weight and the model that is given, it should be noted that W(t) in radians will be W(t) = 0.9cos(2πt/366) + 8.2.
<h3>How to calculate the radian.</h3>
From the information, W(t) = a cos(bt) + d. Firstly, calculate the phase shift, b. At t= 0, the dog is at maximum weight, so the cosine function is also at a maximum. The cosine function is not shifted, so b = 1.
Then calculate d. The dog's average weight is 8.2 kg, so the mid-line d = 8.2. W(t) = a cos t + 8.2. Then calculate a, the dog's maximum weight is 9.1 kg. The deviation from the average is 9.1 kg - 8.2 kg = 0.9 kg. W(t) = 0.9cost + 8.2
Lastly, calculate t. The period p = 2π/b = 2π/1 = 2π. The conversion factor is 1 da =2π/365 rad. Therefore, the function with t in radians is W(t) = 0.9cos(2πt/365) + 8.2.
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