The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.
<h3>What is the derivative of the function g(x) by virtue of the Fundamental theorem of calculus as given in the task content?</h3>
g(x) = Integral; √2 ln(t) dt (with the upper and lower limits e^x and 1 respectively).
Since, it follows from the Fundamental theorem of calculus that given an integral where;
Now, g(x) = Integral f(t) dt with limits a and x, it follows that the differential of g(x);
g'(x) = f(x).
Consequently, the function g'(x) which is to be evaluated in this scenario can be determined as:
g'(x) =
= 1
The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.
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3x
= -------------
3y<span>√2
</span>
x
= -------------
y√2
x√2
= -------------
2y
Answer is A. first choice
Answer:
2a^2b^3 ^3squareroot4a
Step-by-step explanation:
Answer:
$5.20
Step-by-step explanation:
Talked on the phone for 14 minutes .
14 - 3 = 11
11 x .35 = 3.85
3.85 + 1.35 = 5.2