Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
9 (2x-5) =
Remember to look at words that indicate an operation is to take place (Eg: "times" (x) "less than" (-) "Twice x" (2x))
Hope this helps!
We use direct proportionality:
360⁰......Pi×R² (full circle)
120⁰.......x
x=120×pi×R²/360=pi×R²/3
x=pi×4²/3=16.76mi²
A=3×pi cm², for an angle of 2×pi/3=120⁰
In a similar way we compute the area of the full circle:
360.........x
120..........3×pi
x=3×pi×360/120=9×pi=3²×pi.
Thus the radius is 3cm.
Let the number of shaded square be x. And it is given that total number of squares are 25.
Substituting the values
Performing cross multiplication
So 5 squares should be shaded to create a region with a geometric probability of 0.2 .
