All categories

3 years ago

Solve for f -6f = -7f+7 f=?

Mathematics

1 answer:

aniked [119]3 years ago

4 0

Answer:

f = 7

Step-by-step explanation:

-6f = -7f+7

Add 7f to each side

-6f+7f = -7f+7f+7

f = 7

You might be interested in

Remi invests ?600 for 5 years in a saving account. By the end of the 5 years he has received a total of ?75 simple interest. Wor

Allushta [10]

Answer:

2.5 %

Step-by-step explanation:

The simple interest formula is

I = Prt

Data:

I = $75

P = $600

t = 5 yr

Calculation:

75 = 600 × r × 5

75 = 3000 r

Divide each side by 3000

r = 75/3000 = 0.025 = 2.5 % APR

The annual percentage rate is 2.5 %.

4 0

3 years ago

(-3,2); m = 4 write an equation of the line that passes through the given point and has the given slope

Illusion [34]

2=4(-3) + b
2= -12 + b
14= b
Y=4x + 14

6 0

2 years ago

1.Define phase shift. Could every sine function be expressed as a phase shifted cosine function? Explain.

Ann [662]

A phase shift is defined as the a<span>mount of x by which sinusoid is shifted to the left or right.

And yes, </span><span>every sine function be expressed as a phase shifted cosine function:
</span>
sin(t)=cos(90-t)

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

4 0

2 years ago

Use the distributive property to simplify 5(w + 6) =

natulia [17]

Answer:

5w+30

5(w+6)=

5*w= 5w

5*6= 30

3 0

2 years ago

A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair a

vesna_86 [32]

$Chair=x$

$Table=y$

$Desk=z$

$\begin{Bmatrix}x+y&=&40\\y+z&=&83\\x+z&=&77\end{matrix}$

keep the first row as normal, then in the other ones, we can isolate Y and X

$\begin{Bmatrix}x+y&=&40\\y&=&83-z\\x&=&77-z\end{matrix}$

now we can replace at first row...

$\begin{Bmatrix}(77-z)+(83-z)&=&40\\y&=&83-z\\x&=&77-z\end{matrix}$

$\begin{Bmatrix}160-2z&=&40\\y&=&83-z\\x&=&77-z\end{matrix}$

$\begin{Bmatrix}-2z&=&40-160\\y&=&83-z\\x&=&77-z\end{matrix}$

$\begin{Bmatrix}-2z&=&-120\\y&=&83-z\\x&=&77-z\end{matrix}$

$\begin{Bmatrix}z&=&60\\y&=&83-z\\x&=&77-z\end{matrix}$

now we can replace the Z to discovery the other value

$\begin{Bmatrix}z&=&60\\y&=&83-60\\x&=&77-60\end{matrix}$

$\boxed{\boxed{\boxed{\begin{Bmatrix}Chair&=&17\\Table&=&23\\Desk&=&60\end{matrix}}}}$

6 0

3 years ago