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GrogVix [38]
3 years ago
11

I need help again :/

Mathematics
2 answers:
liq [111]3 years ago
7 0

Answer:

They have a 0 in the ones place

Step-by-step explanation:

Because you start with 10, you will always have a 0 at the end.

30, 90, 270, etc.

arsen [322]3 years ago
6 0

Answer:

They have a zero in the ones place.

Step-by-step explanation:

The first one, A., is not always true.

10 * 3 = 30

This does have a a three in the ones place, but watch when we multiply it again.

10 * 30 = 300

Now, it's not true.

B. does not make sense because they would always be an ever number, an d never odd.

C does not make sense either, because they're never odd numbers.

This leaves D, to be the right answer.

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Doss [256]

Answer:

x = 10, AB = 57

Step-by-step explanation:

In a trapezoid, the length of the median is one-half the sum of the lengths of the bases. From this, we have:

\frac{1}{2} (5x + 7 + 8x - 11) = 63

13x - 4 = 126

13x = 130

x = 10

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2 years ago
What is 2√20 - 4√45 + 7√12 in simplest radical form? show steps pls
miss Akunina [59]
Exact Form:
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Decimal Form:
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3 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
3 years ago
Please I need it urgent​
lisabon 2012 [21]

Answer:

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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