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earnstyle [38]
3 years ago
7

Interquartile range n stuff

Mathematics
1 answer:
snow_lady [41]3 years ago
3 0

Answer:

Can u add a better photo please

Step-by-step explanation:

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Mrrafil [7]

The answer is  D, (x + 1) (x + 2) (x - 3)

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3 years ago
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Find the sum..<br><br> 7/4 − (−1/2)<br><br><br> Please Help! I need it now!
8090 [49]

Answer:

1.25

Step-by-step explanation:

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1 year ago
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If s(f) = x-7 and t(x) = 4x^2-x+3, which expression is equivalent to (t•s)(x)
sertanlavr [38]

Answer:

t(s(x)) = 4x^2 -15x +59

Step-by-step explanation:

The expression (t•s)(x) means t(s(x)) or t of s of x.  It means to substitute s(x) into the equation for t(x).

t(s(x)) = 4(x-7)^2 -(x-7) + 3\\t(s(x)) = 4(x^2-14x+49) - x + 7 + 3\\t(s(x)) = 4x^2 - 14x + 49 - x + 10\\t(s(x)) = 4x^2 -15x +59

7 0
4 years ago
Attached you will see the question please help me solve this
Travka [436]

Answer:

the number of tables needed is 16.5

Step-by-step explanation:

198/12=16.5

4 0
3 years ago
A 20-volt electromotive force is applied to an LR-series circuit in which the inductance is 0.1 henry and the resistance is 30 o
Dafna1 [17]

Answer:

i(t)=(2/3)(1-e^{-300t})

Step-by-step explanation:

Before we even begin it would be very helpful to draw out a simple layout of the circuit. Then we go ahead and apply kirchoffs second law(sum of voltages around a loop must be zero) on the circuit and we obtain the following differential equation,

-V +Ldi/dt+Ri=0

where V is the electromotive force applied to the LR series circuit, Ldi/dt is the voltage drop across the inductor and Ri is the voltage drop across the resistor. we can re write the equation as,

di/dt+Ri/L=V/L

Then we first solve for the homogeneous part given by,

di/dt+Ri/L=0

we obtain,

i(t)_{h} =I_{max}e^{-Rt/L}

This is only the solution to the homogeneous part, The final solution would be given by,

i(t)=i(t)_{h} +c

where c is some constant, we added this because the right side of the primary differential equation has a constant term given by V/R. We put this in the main differential equation and obtain the value of c as c=V/R by comparing the constants on both sides.if we put in our initial condition of i(0)=0, we obtain I_{max} =V/R, so the overall equation becomes,

I(t)=(V/R)(1-e^{-Rt/L})

where if we just plug in the values given in the question we obtain the answer given below,

i(t)=(2/3)(1-e^{-300t})

5 0
3 years ago
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