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2 years ago

What's a improper faction of 11/8

Mathematics

2 answers:

dedylja [7]2 years ago

3 0

11/8 is improper
Proper form would be 1 3/8

snow_lady [41]2 years ago

3 0

11/8 is an improper fraction

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Line AB contains points A (8, −4) and B (1, −5). The slope of line AB is....

shutvik [7]

Answer:

$The\ slope\ of\ the\ line\ AB\ is \frac{1}{7} .$

Step-by-step explanation:

Formula for slope

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

As the Line AB contains points A (8, −4) and B (1, −5).

Put points value in the above

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

$m = \frac{- 5- (-4)}{1 - 8}$

$m = \frac{- 5 + 4}{1 - 8}$

$m = \frac{- 1}{-7}$

$m = \frac{1}{7}$

$Therefore\ the\ slope\ of\ the\ line\ AB\ is \frac{1}{7} .$

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Arlecino [84]

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2 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

Now evaluating the integral using calculator,

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$ $= 13.5191$

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2 years ago