How do you factor the trinomial 3x^2+18x-21?

Mathematics

1 answer:

snow_lady [41]3 years ago

7 0

Answer:

(3)(x+7)(x-1)

Step-by-step explanation:

3x^2+18x-21

Let's start by taking 3 out of the equation.

3(x^2+6x-7)

Now, when we factor, we need to find two numbers that add up to 6 and multiply to -7.

The numbers would be 7 and -1.

So the factored form of this would be:

(3)(x+7)(x-1)

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Write the following sets in set-builder notation: (a) The set of all humans whose first name is Tanya or Nelson.

Ulleksa [173]

Answer:

Step-by-step explanation:

Set is a well defined collection of objects .

We can express set in roaster form or set - builder form

<u>Roaster Form</u>

We express elements within curly brackets using commas between the elements .

<u>Set Builder Form</u>

In set builder form , all the elements of the set possess a common property which is not possess by elements outside the set .

We describe the elements of set using a symbol x which is followed by a colon . After colon , we write property possessed by the element and then enclosed the description within curly brackets .

(a)The set of all humans whose first name is Tanya or Nelson

We need to write this one in set builder form .

Define set as follows : { x ∈ H : H is set of all the humans and x is either Tanya or Nelson }

5 0

3 years ago

I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu

ra1l [238]

The imaginary unit $i$ belongs to the set of complex numbers, denoted by $\mathbb C$ . These numbers take the form $a+bi$ , where $a,b$ are any real numbers.

The set of real numbers, $\mathbb R$ , is a subset of $\mathbb C$ , where each number in $\mathbb R$ can be obtained by taking $b=0$ and letting $a$ be any real number.

But any number in $\mathbb C$ with non-zero imaginary part is not a real number. This includes $i$ .

"is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because $2=2+0i$ .

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising $i$ to the $i$ -th power. Since $i=e^{i\pi/2}$ , we have